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3 years ago

How do plant and animal cells compare

1 answer:

6 0

A difference between plant cells and animal cells is that most animal cells are found whereas most plant cells are rectangular. Plant cells have rigid cell wall that surrounds the cell membrane.animals do not have a cell wall

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Explain why vegetables last longer in a fridge.

jeka57 [31]

It has to do with the releasing of ethylene, which speeds up the ripening process

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3 years ago

Read 2 more answers

Please help with the question attached I need it in an hour

lawyer [7]

Answer:

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2 years ago

Elements that have the following qualities: Lustrous, Solid at Room Temperatures, They react and form Basic Compounds, Great con

Tatiana [17]

Answer:

They are classified as METALS.

Explanation:

Elements are simple substances that cannot be chemically broken down into smaller substances. Based on different characteristics, they are classified into 3 namely:

- metals

- non metals and

- metalloid( mainly act as semi- conductor).

METALS are the type of elements that loses electrons to form positive ion, that is, they are electropositive elements. They are distinguished by the following characteristics:

- LUSTROUS: they have the ability to reflect light from its surface.

- At room temperature: Metals are solid are room temperature with the exception of Mercury which is liquid at room temperature.

- They react and form Basic Compounds

- Great conductor: most metals are great conductors of heat and electricity because they possess free electrons.

- Melting Point: they have high melting points.

8 0

3 years ago

The principal source of sulfur on earth is deposits of free sulfur occurring mainly in volcanically Active regions. The offer wa

aivan3 [116]

Answer:

1.18x10⁸L of SO₂ and 2.36x10⁸L of H₂S

Explanation:

The balanced reaction is:

8SO₂(g) + 16H₂S(g) → 16H₂O(l) + 3S₈(s)

To solve this question we must find the moles of S₈ in 4.50x10⁵kg. With these moles and the reaction we can find the moles of SO₂ needed to react (Twice these moles = Moles Of H₂S needed). Using PV = nRT we can find the volume of the gas required:

Moles S₈ - molar mass: 256.52g/mol-

4.50x10⁵kg = 4.50x10⁸g * (1mol / 256.52g) =

1.75x10⁶ moles S₈

Moles SO₂:

1.75x10⁶ moles S₈ * (8mol SO₂ / 3mol S₈) = 4.68x10⁶ moles SO₂

Moles H₂S:

4.68x10⁶ moles SO₂ * 2 = 9.36x10⁶ moles H₂S

The volume could be obtained as follows:

PV = nRT

V = nRT / P

V is volume in liters

n are moles: 4.68x10⁶ moles SO₂ and 9.36x10⁶ moles H₂S

R is gas constant = 0.082atmL/molK

T is absolute temperature = 22°C + 273.15 = 295.15K

P is pressure = 0.961atm

Replacing:

Volume SO₂ and H₂S:

4.68x10⁶ moles * 0.082atmL/molK * 295.15K / 0.961atm =

9.36x10⁶ moles H₂S * 0.082atmL/molK * 295.15K / 0.961atm =

5 0

2 years ago

Calculate the ph of a dilute solution that contains a molar ratio of potassium acetate to acetic acid (pka ???? 4.76) of (a) 2:1

givi [52]

According to Hasselbach-Henderson equation:

$pH=pK_{a}+log\frac{[A^{-}]}{[HA]}$

Here, $[A^{-}]$ is concentration of conjugate base and [HA] is concentration of acid.

In the given problem, conjugate base is $CH_{3}COOK$ and acid is $CH_{3}COOH$ thus, Hasselbach-Henderson equation will be as follows:

$pH=pK_{a}+log\frac{[CH_{3}COOK]}{[CH_{3}COOH]}$ ...... (1)

(a) Ratio of concentration of potassium acetate and acetic acid is 2:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=2$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{2}{1}=5.06$

Therefore, pH of solution is 5.06.

(b) Ratio of concentration of potassium acetate and acetic acid is 1:3 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{3}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{3}=4.28$

Therefore, pH of solution is 4.28.

(c)Ratio of concentration of potassium acetate and acetic acid is 5:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{5}{1}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{5}{1}=5.45$

Therefore, pH of solution is 5.45.

(d) Ratio of concentration of potassium acetate and acetic acid is 1:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=1$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{1}=4.76$

Therefore, pH of solution is 4.76.

(e) Ratio of concentration of potassium acetate and acetic acid is 1:10 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{10}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{10}=3.76$

Therefore, pH of solution is 3.76.

4 0

3 years ago