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Stolb23 [73]
3 years ago
10

The number of grams present in 1.35 mol of Fe is

Chemistry
1 answer:
BlackZzzverrR [31]3 years ago
5 0
First you need to find the mass of one mole of the element. (say Fe) Find Fe on the periodic table, it should tell you what the average atomic mass is. The average atomic mass = mass of one mole.(in this case it is 55.85g) Take your moles (1.35mol Fe) and multiply it by the mass of one mole (55.85g) 1.35mol*55.85g/mol=75.39g (Just repeat that method for the other problems) use the formula <span><span>moles=<span><span>mass</span><span>Molar mass

</span></span></span></span>
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It’s 3 because iv done this before
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Write and balance the half-reaction for the oxidation of white phosphorous P4 to the phosphate ion PO3^−4 in a basic solution.
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Since the half-reaction is occurring in a basic solution, add 32OH− to each side of the equation to eliminate the H+ ions.

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Final reaction :

P₄ + 32OH⁻ ⟶ 4PO₃⁻⁴ + 16H₂O + 20e⁻

A half reaction is either the oxidation or reduction reaction component of a redox reaction. A half reaction is obtained by considering the change in oxidation states of individual substances involved in the redox reaction.

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4 0
2 years ago
What is the answer to...
adoni [48]

Answer: short answer short 0.65 / 5.37

15% NaOH by mass is 15g of NaOH in (100-15)g of solution.

No. Of moles of NaOH in solution = 0.65

No of moles of Water in solution = 4.72

Mole Fraction =  

(

(Moles of Solvent)

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)

OR

(

(Moles of Solvent)

Total Number Of Moles

)

= 0.65 / 5.37

= 0.121

Explanation:

Hope this helped

8 0
3 years ago
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