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anyanavicka [17]
4 years ago
14

Write Huckel's rule below and determine how many electrons are required to make an aromatic ring with n = 0, 1, and 2.

Chemistry
1 answer:
lisov135 [29]4 years ago
4 0

<u>Answer:</u> The number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.

<u>Explanation:</u>

Huckel's rule is used to determine the aromaticity in a compound. The number of delocalized \pi- electrons are calculated by using the equation:

\text{Number of delocalized }\pi-\text{ electrons}=4n+2

where,

n = 0 or any whole number

  • Calculating the value of electrons for n = 0

Putting values in above equation, we get:

\text{Number of delocalized }\pi-\text{ electrons}=4(0)+2=2

  • Calculating the value of electrons for n = 1

Putting values in above equation, we get:

\text{Number of delocalized }\pi-\text{ electrons}=4(1)+2=6

  • Calculating the value of electrons for n = 2

Putting values in above equation, we get:

\text{Number of delocalized }\pi-\text{ electrons}=4(2)+2=10

Hence, the number of electrons for n = 0, 1 and 2 are 2, 6 and 10 respectively.

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<h3>Further explanation</h3>

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Solution

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\tt ln(\dfrac{P_1}{P_2})=\dfrac{-\Delta H_{vap}}{R}(\dfrac{1}{T_1}-\dfrac{1}{T_2})

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Input given values :

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More on stoichiometric calculations can be found here: brainly.com/question/27287858

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