<h2>A : Hamstrings</h2><h2 /><h2>B : Ligament</h2><h2 /><h2>C : Meniscus</h2><h2 /><h2>D : * think this is Ligament too! hope im right</h2><h2 /><h2>E : Femur (Thigh Bone)</h2>
The water will boil at C) 80°C
<h3>Further explanation</h3>
Given
Vapour pressure of water = 47 kPa
Required
Boiling point of water
Solution
We can use the Clausius-Clapeyron equation :

Vapour pressure of water at boiling point 100°C=101.325 kPa
ΔH vap for water at 100°C=40657 J/mol
R = 8.314 J/mol K
T₁=boiling point of water at 101.325 kPa = 100+273=373 K
Input given values :

From rocks and lava and earthquakes
The mass of
that would be formed will be 18.22 grams
<h3>Stoichiometric calculations</h3>
Let us first look at the balanced equation of the reaction:

The mole ratio of Y to
is 2:3.
Mole of 10.0 grams of Y = 10/88.9 = 0.11 moles
Mole of 10.0 grams
= 10/71 = 0.14 moles
3/2 of 0.11 = 0.165. Thus,
is limiting in availability.
Mole ratio of
and
= 3:2
Equivalent mole of
= 2/3 x 0.14 = 0.093 moles.
Mass of 0.093 moles
=0.093 x 195.26 = 18.22 grams
More on stoichiometric calculations can be found here: brainly.com/question/27287858
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