Question

A 1.5 kg copper block is given an initial speed of3.00m/s on a

Answer 1

Answer:

a. 0.01 C

b. dissipated to outside environment

Explanation:

Let the specific heat of copper be 0.3846 kJ/kg-K or 384.6 J/kg-C

(a)The original kinetic energy of the block is:

$E_k = \frac{mv^2}{2} = \frac{1.5*3^2}{2} = \frac{1.5*9}{2} = 6.75 J$

As 85% of this kinetic energy is converted to block internal heat energy, with specific heat we can calculate the rise in temperature:

$E_h = 0.85E_k = 0.85*6.75 = 5.7375 J$

$mc_c\Delta T = 5.7375$

$1.5*384.6\Delta T = 5.7375$

$\Delta T = \frac{5.7375}{1.5*384.6} \approx 0.01^oC$

(b) the remaining 15% energy would probably be dissipated to outside environment as heat energy