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VLD [36.1K]
3 years ago
14

A projectile is fired with an initial speed of 51.2 m/s at an angle of 44.5 degrees above the horizontal on a long flat firing r

ange. Determine the following: a. The maximum height reached by the projectile. b. The total time in the air. c. The total horizontal distance covered (that is, the range)
Physics
1 answer:
irinina [24]3 years ago
3 0
Use the projectile motion equations

H = v^2 x sin^2(θ) ÷ 2g

t = 2 x v x sinθ ÷ g

R = v^2 x sin2θ ÷ g
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larisa [96]

Answer:

wow i have know idea

Explanation:

5 0
3 years ago
Why plate tectonics is a scientific theory and not a scientific law.
ser-zykov [4K]

Answer:

We have not drilled to the center of the earth.

Explanation:

7 0
3 years ago
Suppose that a simple pendulum consists of a small 60.0 g bob at the end of a cord of negligible mass. If the angle 0 between th
erik [133]

Based on the mass of the bob and the angle between the cord and the vertical, the pendulum length is 0.50m.

The maximum kinetic energy can be found to be 9.42 x 10⁻⁴J.

<h3>What is the pendulum length?</h3>

This can be found as:

= g-force / w²

Solving gives:

= 9.8 / 4.43²

= 0.4998 m

= 0.50 m

<h3>What is the maximum kinetic energy?</h3>

This can be found as:

= 0.5 × m × w² × A²

Maximum kinetic energy is:

= 0.5 × 60 × 10⁻³ × (4.43 × 0.4998 x 0.08 rad)²

= 9.42 x 10⁻⁴J

Find out more on maximum kinetic energy at brainly.com/question/24690095.

5 0
2 years ago
ow long must a simple pendulum be if it is to make exactly ten swings per second? (That is, one complete vibration takes exactly
Igoryamba
The period T of a pendulum is given by:
T=2 \pi  \sqrt{ \frac{L}{g} }
where L is the length of the pendulum while g=9.81 m/s^2 is the gravitational acceleration.

In the pendulum of the problem, one complete vibration takes exactly 0.200 s, this means its period is T=0.200 s. Using this data, we can solve the previous formula to find L:
L=g ( \frac{T}{2\pi} )^2=(9.81 m/s^2)( \frac{0.2 s}{2 \pi} )^2=1 \cdot 10^{-3} m=1 mm
4 0
3 years ago
How far will a car travel in 25 seconds at 10m/ min
Kryger [21]
Time = 25s
speed = 10m/min
= 10m / 60
= (1/6)m/s


distance = speed × time
= 25 × (1/6)
=4.167m
7 0
3 years ago
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