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Fittoniya [83]
3 years ago
7

A dilute solution is prepared by transferring 40.00 ml of a 0.3433 m stock solution to a 750.0 ml volumetric flask and diluting

to mark. what is the molarity of this dilute solution?
Chemistry
1 answer:
alina1380 [7]3 years ago
5 0
We are given with the initial volume of the substance and the molarity. The first thing that needs to be done is to multiply the equation in order to obtain the number of moles such as shown below.
  
    number of moles = (40 mL) x (1 L / 1000 mL) x (0.3433 moles / L)
           number of moles = 0.013732 moles

To get the value of the molarity of the diluted solution, we divide the number of moles by the total volume.
          molarity = (0.013732 moles) / (750 mL / 1000 mL/L) = 0.0183 M

Similarly, we can solve for the molarity by using the equation,
           M₁V₁ = M₂V₂
Substituting the known values in the equation,
     (0.3433 M)(40 mL) = M₂(750 mL)
              M₂ = 0.0183 M
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ANSWER:

The melting and boiling points increase in order of increasing atomic number.

The size of the nucleus increases in order of increasing atomic number.

Ionization energy decreases in order of increasing atomic number.

Electronegativity decreases in order of increasing atomic number.

Electron Affinity decreases in order of increasing atomic number.

The reactivities decrease in order of increasing atomic number.

EXPLANATION:

NAME     MELTING POINT    BOILING POINT

Fluorine    -220              -188

Chlorine          -101                       -35

Bromine           -7.2                58.8

Iodine            114                184

Melting and Boiling points increase as shown above.

NAME     COVALENT RADIUS    IONIC RADIUS

Fluorine    71                        133

Chlorine          99                          181

Bromine           114                  196

Iodine            133                 220

Size increases as shown above.

NAME            FIRST IONIZATION ENERGY

Fluorine              1681

Chlorine             1251

Bromine              1140

Iodine               1008

Ionization energy decreases as shown above.

NAME        ELECTRONEGATIVITY

Fluorine     4

Chlorine           3

Bromine           2.8

Iodine            2.5

Electronegativity decreases as shown above.

NAME      ELECTRON AFFINITY

Fluorine    -328.0

Chlorine    -349.0

Bromine    -324.6

Iodine     -295.2

Electron affinity decreases as shown above.

REACTIVITY

The reactivities of the halogens decrease. This is due to the fact that atomic radius increases in proportion with an increase of electronic energy levels. This decreases the pull for valence electrons of other atoms, minimizing reactivity.

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