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ikadub [295]
4 years ago
13

A certain object has a very high specific heat. The object is heated over a flame for 1 minute. The flame is shut off, and the o

bject is allowed to cool down for one minute. The object most likely: A. heats up quickly and cools down quickly. B. heats up quickly and cools down slowly. C. heats up slowly and cools down quickly. D. heats up slowly and cools down slowly.
Chemistry
1 answer:
ra1l [238]4 years ago
3 0
The answer to this question is the letter D which is "heats up slowly and cools down slowly". The water will take more time to heat since water has a high specific heat capacity and it will take time also to cool down because of same reason. Turning off the stove does not mean that it will take a few seconds to cool down.
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Number of Mg(OH)2 formula units in 7.40 moles of Mg(OH)2.
-Dominant- [34]
The answer is 4.45 × 10²⁴ units.

To calculate this, we will use Avogadro's number which is the number of units (atoms, molecules) in 1 mole of substance:
6.02 × 10²³ units per 1 mole

So, we need a proportion:
If 6.02 × 10²³ units are in 1 mole, how many units will be in 7.40 moles:
6.02 × 10²³ units : 1 mole = x : 7.40 moles

After crossing the products:
1 mole * x =  7.40 moles * 6.02 × 10²³ units
x = 7.40 * 6.02 × 10²³ units
x = 44.5 × 10²³ units = 4.45× 10²⁴ unit
5 0
3 years ago
A container is at a pressure of 3 atm and a temperature of 280K. What is the new temperature when the pressure is reduced to 1.5
GenaCL600 [577]

Answer:

140 K

Explanation:

Step 1: Given data

  • Initial pressure of the gas (P₁): 3 atm
  • Initial temperature of the gas (T₁): 280 K
  • Final pressure of the gas (P₂): 1.5 atm
  • Final temperature of the gas (T₂): ?

Step 2: Calculate the final temperature of the gas

We have a gas whose pressure is reduced. If we assume an ideal behavior, we can calculate the final temperature of the gas using Gay-Lussac's law.

T₁/P₁ = T₂/P₂

T₂ = T₁ × P₂/P₁

T₂ = 280 K × 1.5 atm/3 atm = 140 K

6 0
3 years ago
Propanoic acid, ch3ch2cooh, has a pka =4.9. draw the structure of the conjugate base of propanoic acid and give the ph above whi
xenn [34]

Conjugate base of Propanoic acid (CH_{3}CH_{2}COOH is propanoate where -COOH group gets converted to -COO^{1-}. The structure of conjugate base of Propanoic acid is shown in the diagram.

The p^{H} above which 90% of the compound will be in this conjugate base form can be determined using Henderson's equation as propanoic acid is weak acid and it can form buffer solution on reaction with strong base.

p^{H}= p^{k_{a}+ log\frac{[Conjugate base]}{[acid]}=4.9+log\frac{90}{10}=5.85

As 90% conjugate base is present, so propanoic acid present 10%.

8 0
4 years ago
How many milligrams of a 20mg sample of cesium-137 remain after 60 years
andrey2020 [161]
Cs -137 has a half life of about 30 years. If 60 years pass, there is two half lives passed so 1/2 * 1/2= 1/4. Take 1/4 and multiply it with the mass given:
(1/4)*20mg=5mg left
5 0
3 years ago
The polymerization of amino acids produces:
Delicious77 [7]

Answer:

Proteins

Explanation:

Polymerization, in chemistry, is the chemical combination of monomeric units to form a polymer. Polymers are large molecules made up of smaller units called monomers. Amino acids are the monomeric units of proteins i.e. A protein is made up of of many amino acids joined together.

Therefore, the chemical combination of amino acids will form a peptide bond between the carbon atom of the acid group and nitrogen atom of the amine group in the structure of the amino acids. This is done by the loss of a water molecule. The continuous repetition of this polymerization process will form a chain called polypeptide, which is the PROTEIN.

8 0
3 years ago
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