Answer:
a) ΔG = 1688.5 J/mol = 1.7 kJ/mol
b) ΔG = 21673.3 J/mol = 21.7 kJ/mol
Explanation:
Step 1: Data given
Temperature = 20.0 °C = 293 K
Initial temperature = 1.0 bar = 0.986923 atm
Final temperature = 2.0 bar = 1.97385 atm
Step 2: Calculate
ΔG = RT * ln (Pt / Pi)
⇒with R = 8.314 J/K* mol
⇒with T = 293K
⇒with Pt = final pressure = 1.97385 atm
⇒with Pi = the initial pressure = 0.986923 atm
ΔG = 8.314 J/mol*K *293 K * ln (1.97385/0.986923)
ΔG = 8.314 J/mol*K *293 K * 0.693
ΔG = 1688.5 J/mol = 1.7 kJ/mol
(b) 0.000 27 atm
Step 3:
ΔG = RT * ln (Pt / Pi)
⇒with R = 8.314 J/K* mol
⇒with T = 293K
⇒with Pt = final pressure = 1.97385 atm
⇒with Pi = the initial pressure = 0.00027 atm
ΔG = 8.314 J/mol*K *293 K * ln (1.97385/0.00027)
ΔG = 8.314 J/mol*K *293 K * 8.897
ΔG = 21673.3 J/mol = 21.7 kJ/mol
