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belka [17]
3 years ago
10

The data in the table are the result of a paramecium being placed in a hypertonic salt solution.

Chemistry
2 answers:
dlinn [17]3 years ago
7 0

Answer: salt concentration outside paramecium

Explanation:

kolezko [41]3 years ago
3 0
<span>the answer is
C. The bar for very low concentration is twice the height of the bar for medium concentration.

proof
</span>
<span>
</span>
<span>Medium--------------------15

</span>Very Low-------------------30 = 2<span /> x 15 (<span>Medium)
</span>



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Susan needs to simplify the expression shown below what should be her first step
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Susan should follow PEMDAS,

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So, the first step should be, to solve the equation in the parentheses.

I hope this helps!
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How do you know that some substances in coffee beans are soluble?
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6 0
3 years ago
The teal line of the hydrogen emission spectrum has a wavelength of 486.0 nm. A hydrogen emission spectrum has a violet, a blue,
Sloan [31]

Answer:

The correct answer to the following question will be "4.08 × 10⁻¹⁹ Joule".

Explanation:

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Wavelength, λ = 486.0 nm

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E=h\upsilon =\frac{hc}{\lambda}

On putting the estimated values, we get

⇒          =\frac{1241.5 \ ev\ nm}{486 \ nm}

⇒          =2.554 \ ev

∴ 1 ev = 1.6 × 10⁻¹⁹ J

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7 0
3 years ago
A sample of pure lithium chloride contains 16% lithium by mass. What is the % lithium by mass in a sample of pure lithium carbon
Anna35 [415]

Answer:

Percentage lithium by mass in Lithium carbonate sample = 19.0%

Explanation:

Atomic mass of lithium = 7.0 g; atomic mass of Chlorine = 35.5 g; atomic mass of carbon = 12.0 g; atomic mass of oxygen = 16.0 g

Molar mass of lithium chloride, LiCl = 7 + 35.5 = 42.5 g

Percentage by mass of lithium in LiCl = (7/42.5) * 100% = 16.4 % aproximately 16%

Molar mass of lithium carbonate, Li₂CO₃ = 7 * 2 + 12 + 16 * 3 =74.0 g

Percentage by mass of lithium in Li₂CO₃ = (14/74) * 100% = 18.9 % approximately 19%

Mass of Lithium carbonate sample = 2 * 42.5 = 85.0 g

mass of lithium in 85.0 g Li₂CO₃ = 19% * 85.0 g = 16.15 g

Percentage by mass of lithium in 85.0 g Li₂CO₃ = (16.15/85.0) * 100 % = 19.0%

Percentage lithium by mass in Lithium carbonate sample = 19.0%

3 0
3 years ago
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