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belka [17]
3 years ago
10

The data in the table are the result of a paramecium being placed in a hypertonic salt solution.

Chemistry
2 answers:
dlinn [17]3 years ago
7 0

Answer: salt concentration outside paramecium

Explanation:

kolezko [41]3 years ago
3 0
<span>the answer is
C. The bar for very low concentration is twice the height of the bar for medium concentration.

proof
</span>
<span>
</span>
<span>Medium--------------------15

</span>Very Low-------------------30 = 2<span /> x 15 (<span>Medium)
</span>



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How molecules of N2 gas can be present in a 2.5 L flask at 50°C and 650 mmHg?
ratelena [41]

Answer:

0.482 ×10²³ molecules

Explanation:

Given data:

Volume of gas = 2.5 L

Temperature of gas = 50°C (50+273 = 323 k)

Pressure of gas = 650 mmHg (650/760 =0.86 atm)

Molecules of N₂= ?

Solution:

PV= nRT

n = PV/RT

n = 0.86 atm × 2.5 L /0.0821 atm. mol⁻¹. k⁻¹. L × 323 k

n = 2.15 atm. L /26.52 atm. mol⁻¹.L

n = 0.08 mol

Number of moles of N₂ are 0.08 mol.

Number of molecules:

one mole = 6.022 ×10²³ molecules

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O. How many protons, neutrons and electrons are in Neodymium - 144 (Nd-144)?
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When a rock falls from outer space all the way to the groung, its called a?
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It's called a meteorite.
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How much heat, in joules, must be added to a 75.0-g iron block with a specific heat of 0.449 J/g °C to increase its temperature
svp [43]

Answer:

50,849.25 Joules

Explanation:

The amount of heat, Q, required to raise the temperature of a body with mass, m, and specific heat capacity, c is given by:

Q = mcΔT, where ΔT represents the change in temperature.

In the case of the iron block:

m = 75 g

c = 0.449 J/g °C

ΔT = 1535 - 25 = 1510 °C

Therefore,

Q = 75 g x 0.449 J/g °C x 1510 °C

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When the reaction shown is correctly balanced, the coefficients are HNO3 + KOH → KNO3 + H2O
GuDViN [60]
Coefficients are 1,1,1,1
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