The data in the table are the result of a paramecium being placed in a hypertonic salt solution.
2 answers:
Answer: salt concentration outside paramecium
Explanation:
<span>the answer is
C. The bar for very low concentration is twice the height of the bar for medium concentration.
proof
</span>
<span>
</span>
<span>Medium--------------------15
</span>Very Low-------------------30 = 2<span /> x 15 (<span>Medium)
</span>
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