Answer:
(a) Length =136.58 m
(b) T=5995 N
Explanation:
for the glider in the back
T - 1900 = 700 a
for the glider in front
12000-T -1900 = 700a
add equations
12000-3800 = 1400 a
a=5.85 m/s^2
v^2 = v0^2 + 2 a x
40^2 = 2*5.85*x
Length =136.58 m
b) plug the a back into one of the previous formula
T - 1900 = 700*5.85
T=5995 N
Answer:
D) directly, inversely
Explanation:
The energy of a photon of light is directly proportional to its frequency and inversely proportional to its wavelength.
Frequency is the number of waves that passes through a point per unit of time.
Wavelength is the is the distance between successive crests or troughs on a wave.
Mathematically, frequency is related to wavelength and velocity using;
Energy = h x f
where h is the Planck's constant
f is the frequency
Since c = f ∧
where f is the frequency of the wave
∧ is the wavelength of the wave
c is the speed of light
So;
f = c/∧
Therefore;
E = 
From the equation, we see an inverse relationship between E and wavelength and a direct one with frequency.
Well, since you only want direction, ignore the numbers. Use the right hand rule.
Current (pointer finger) points west (left).
Magnetic field (middle finger) points south (towards you).
Force (thumb) then points up (away from the earth)
Answer:
Cable color codes are very important for example, If something is not wired properly, it can result in injuries, deaths, fires, and many other problems. This is why there are well-established wire color codes to ensure those working with an around this type of equipment can ensure everything is wired safely and effectively. If we used three phase cables without color code, this can lead too incorrect things that might be a hazard too get not fix and learning new color codes would be hard therefore we should stick too the same color codes for cables and it saves the hassle for needing too check every cable cord color then the original one signed too it.
First, we convert kcal to joules:
1 kcal = 4.184 kJ
475 kcal = 1987.4 kJ
Now, calculating the change in internal energy:
ΔU = Q + W; where Q is the heat supplied to the system and W is the work done on the system.
ΔU = -500 + 1987.4
ΔU = 1487.4 kJ
