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3 years ago

BTSAUDY5 NAME STARTS FROM THIS

Engineering

2 answers:

otez555 [7]3 years ago

7 0

Answer:

What's your question?

Explanation:

I'm not able to understand it....

Sorry.

Triss [41]3 years ago

6 0

What is your question

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Steam enters an adiabatic turbine at 10MPa and 500 C and leaves at 10 kPa with a quality of 90%. Neglecting the changes in kinet

Amanda [17]

Answer:

flow ( m ) = 4.852 kg/s

Explanation:

Given:

- Inlet of Turbine

P_1 = 10 MPa

T_1 = 500 C

- Outlet of Turbine

P_2 = 10 KPa

x = 0.9

- Power output of Turbine W_out = 5 MW

Find:

Determine the mass ow rate required

Solution:

- Use steam Table A.4 to determine specific enthalpy for inlet conditions:

P_1 = 10 MPa

T_1 = 500 C ---------- > h_1 = 3375.1 KJ/kg

- Use steam Table A.6 to determine specific enthalpy for outlet conditions:

P_2 = 10 KPa -------------> h_f = 191.81 KJ/kg

x = 0.9 -------------> h_fg = 2392.1 KJ/kg

h_2 = h_f + x*h_fg

h_2 = 191.81 + 0.9*2392.1 = 2344.7 KJ/kg

- The work produced by the turbine W_out is given by first Law of thermodynamics:

W_out = flow(m) * ( h_1 - h_2 )

flow ( m ) = W_out / ( h_1 - h_2 )

- Plug in values:

flow ( m ) = 5*10^3 / ( 3375.1 - 2344.7 )

flow ( m ) = 4.852 kg/s

3 0

3 years ago

Explain what will happen if the series circuit is closed?

irakobra [83]

Answer:

When the circuit switch is off, no electricity will flow and then the circuit is called an open circuit. Electricity will not flow in open circuit.

5 0

3 years ago

Read 2 more answers

The principal component in glass manufacturing is_____

Oksanka [162]

Answer:

Silica is the principal component in glass.

Explanation:

Step1

Glass is the amorphous solid and transparent. Glass products have many of the shapes and design that are available in market.

Step2

Natural quartz is the primary source of glass in sand. Silica is the principal component in approximately all glass. Lime stone, soda ash and aluminum oxide are added in the galas for desired properties depending upon application. So, silica is the principal component in glass.

5 0

4 years ago

Licemer1 [7]

Answer:

none of the above

hope this is helpful

7 0

3 years ago

Calculate the De-Broglie wavelength for electron accelerated across a potential of 10V, 100V, 1000V, and 10kV respectively. Whic

Arlecino [84]

Answer:

a) $\lambda=3.87 \r A$

b) $\lambda=1.23 \r A$

c) $\lambda=0.387 \r A$

d) $\lambda=0.123 \r A$

Explanation:

We know that the kinetic energy can be expressed in terms of momentum (p= mv):

$K=\frac{p^{2}}{2m}$

p is the momentum
m is the mass of the particle

So, the momentum will be:

$p=\sqrt{2mK}$ (1)

We can use the energy conservation to relate K and the electric potential energy. We assume that all potential energy becomes kinetic energy. Therefore:

$K=q_{e}V$ (2)

a) If V=10 [V], K will be:

$K=1.6*10^{-19}*10=1.6*10^{-18}[J]$

We can find the momentum using the equation (1)

$p=\sqrt{2*9.1 x 10^{-31}*1.6*10^{-18}}=1.71*10^{-24}[kg*m*s^{-1}]$

The De-Broglie wavelength equation is given by:

$\lambda=\frac{h}{p}$ (3)

h is the Plank constant ( $h=6.626 x 10^{-34} [J*s]$ )

$\lambda=\frac{6.626 x 10^{-34}}{1.71*10^{-24}}=3.87*10^{-10}[m]=3.87 \r A$

b) If V=100 [V], using the same analyze, the De-Broglie wavelength will be:

$K=1.6*10^{-19}*100=1.6*10^{-17}[J]$

$p=\sqrt{2*9.1 x 10^{-31}*1.6*10^{-17}}=5.39*10^{-24}[kg*m*s^{-1}]$

$\lambda=\frac{6.626 x 10^{-34}}{5.39*10^{-24}}=1.23*10^{-10}[m]=1.23 \r A$

c) V=1000 [V]

$K=1.6*10^{-19}*100=1.6*10^{-16}[J]$

$p=\sqrt{2*9.1 x 10^{-31}*1.6*10^{-16}}=1.71*10^{-23}[kg*m*s^{-1}]$

$\lambda=\frac{6.626 x 10^{-34}}{1.71*10^{-23}}=3.87*10^{-11}[m]=0.387 \r A$

d) V=10000 [V]

$K=1.6*10^{-19}*100=1.6*10^{-15}[J]$

$p=\sqrt{2*9.1 x 10^{-31}*1.6*10^{-15}}=5.40*10^{-23}[kg*m*s^{-1}]$

$\lambda=\frac{6.626 x 10^{-34}}{5.40*10^{-23}}=1.23*10^{-11}[m]=0.123 \r A$

The fringe spacing interference is proportional to the wavelength, so in our case, the larger fringe spacing occurs when voltage is 10 V, here λ = 3.87 angstroms.

I hope it helps you!

5 0

3 years ago