Charge can be transferred from one object to another in three way conduction, polarization, and friction
Whenever electrons are transferred between objects, neutral matter becomes charged and three ways this can occur are referred to as conduction, polarization, and friction conduction means when there is direct contact between materials that differ in their ability to give up or accept electrons when two different materials are rubbed together, there is a transfer of electrons from one material to the other material and this causes one object to become positively charged (the electron loser) and the other object to become negatively charged (the electron gainer)
Here given object is water + balloon; balloon + wall; tape then you rub a balloon against your clothes and it sticks to the wall, you are adding a surplus of electrons (negative charges) to the surface of the balloon the wall is now more positively charged than the balloon and we tested the conductivity of deionized water positively charged
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The coefficients next to the symbols of entities indicate the number of moles of a substance produced or used in the chemical reaction.
I believe the correct answer from the choices listed above is the second option. For liquids, it is the temperature that affects vapor pressure. <span>The </span>vapor pressure<span> of any substance increases non-linearly with </span>temperature<span> according to the Clausius–Clapeyron </span>relation<span>. Hope this helps. Have a nice day.</span>
The grams of potassium chlorate that are required to produce 160 g of oxygen is 408.29 grams
<u><em>calculation</em></u>
2 KClO₃→ 2 KCl + 3O₂
Step 1: find the moles of O₂
moles = mass÷ molar mass
from periodic table the molar mass of O₂ = 16 x2 = 32 g/mol
moles = 160 g÷ 32 g/mol = 5 moles
Step2 : use the mole ratio to determine the moles of KClO₃
from equation given KClO₃ : O₂ is 2:3
therefore the v moles of KClO₃ = 5 moles x 2/3 = 3.333 moles
Step 3: find the mass of KClO₃
mass= moles x molar mass
from periodic table the molar mass of KClO₃
= 39 + 35.5 + (16 x3) =122.5 g/mol
mass = 3.333 moles x 122.5 g/mol =408.29 grams
Answer:
<em>249 kJ</em>
Explanation:
To obtain the energy change of the reaction:
H₂O → H₂ + ¹/₂ O₂
It is necessary to obtain the difference between bond energy of the products and bond energy of the reactant, thus:
Energy of products:
1 mol of H-H bond × 436 kJ/mol = 436 kJ
¹/₂ mol of O=O bond × 498 kJ/mol = 249 kJ
Energy of reactant:
2 mol of H-O bond × 467 kJ/mol = 934 kJ
Energy change of the reaction is:
934 kJ - (436 kJ + 249 kJ) = <em>249 kJ</em>
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I hope it helps!
