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jasenka [17]
4 years ago
13

Your brother is insisting that you'll never hear a sound produced behind a barrier wall at the end of your yard. You notice that

the door within the wall is open and quickly explain to him that the sound will be able to reach you due to
Physics
2 answers:
Neko [114]4 years ago
8 0
Due to the barrier being broken the sound will go threw but if the door was closed all the way it would be different and there would be no space for the sound to slip threw
In-s [12.5K]4 years ago
4 0

Answer:

Explanation:

The sound is a longitudinal wave that when it hits an obstacle is reflected, but in the part where the door is open it does not find the obstacle, so the diffraction phenomenon can occur if the incident wavelength is less than or equal to the size of the opening.

This diffraction phenomenon is well known and gives rise to part where the sound has a high intensity and others where it is attenuated, following the relationship

   sin θ = λ / a

Where the angle is measured from the center of the opening, a  is the width of the door and λ is the wavelenght of sound.

If we analyze the audible frequencies a little, they are in the range of 20 Hz to 20000Hz, and since the sound velocity is of the order of 343m / s, we can look for its wavelength range

    v = λ f

    λ = v / f

Therefore, the wave languages ​​are in the range of 17 m to 0.017 m, so we can see that almost all wavelengths can pass through the diffraction phenomenon.

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You push on a box with a force of 300 N directly north. Another person pushes the box with a
tangare [24]

Answer:

resultant \\  \: F =  \sqrt{ {300}^{2} +  {600}^{2}  }  \\  =  \sqrt{450000}  \\  = 670.82 \: newtons

7 0
3 years ago
A runner moves west with an initial velocity of 4 m/s. She accelerates 3 m/s2 for 30 seconds. The runner's final velocity is
Firlakuza [10]

Answer:

v = 94m/s

Explanation:

Using the first equation of motion

v = u + at

u = 4m/s , a = 3m/s² , t = 30s , v = ?

v = u + at

v = 4 + 3 × 30

v = 4 + 90

v = 94m/s

I hope this was helpful, please mark as brainliest

3 0
3 years ago
What is the initial velocity of the object represented by the graph?
Arturiano [62]

Initial velocity of the object: 5 m/s

Explanation:

The figure in the problem is missing: find it in attachment.

The graph in the figure represents the velocity of an object (v) versus the time passed (t).

Here we are asked to find the initial velocity of the object.

This means that we have to find the velocity of the object when the time is zero, so when

t = 0

By looking at the corresponding value on the y-axis (velocity), we see that when t = 0, then

v = 5 m/s

Therefore, the initial velocity of the object is 5 m/s.

Learn more about velocity:

brainly.com/question/5248528

#LearnwithBrainly

5 0
3 years ago
Read 2 more answers
an impulse is a force acting over some amount of time to cause a change in momentum. on the other hand, work is a
finlep [7]

Answer:

force; distance; energy.

Explanation:

An impulse can be defined as the net force acting an object for a very short period of time.

Mathematically, impulse is given by the formula;

Impulse = force * time

An impulse is a force acting over some amount of time to cause a change in momentum. On the other hand, work is a force acting over some amount of distance to cause a change in energy.

Mathematically, work done is given by the formula;

Work done = force * distance

4 0
3 years ago
28. A stone is projected at a cliff of height h with an initial speed of 42.0 mls directed at angle θ0 = 60.0° above the horizon
Julli [10]

Answer:

a) 51.8 m, b) 27.4 m/s, c) 142 m

Explanation:

Given:

v₀ = 42.0 m/s

θ = 60.0°

t = 5.50 s

Find:

h, v, and H

a) y = y₀ + v₀ᵧ t + ½ gt²

0 = h + (42.0 sin 60.0) (5.50) + ½ (-9.8) (5.50)²

h = 51.8 m

b) vᵧ = gt + v₀ᵧ

vᵧ = (-9.8)(5.5) + (42.0 sin 60.0)

vᵧ = -17.5 m/s

vₓ = 42.0 cos 60.0

vₓ = 21.0 m/s

v² = vₓ² + vᵧ²

v = 27.4 m/s

c) vᵧ² = v₀ᵧ² + 2g(y - y₀)

0² = (42.0)² + 2(-9.8)(H - 51.8)

H = 142 m

4 0
4 years ago
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