Question

The morning of a birthday party, a balloon is filled with 8.5 L of helium (He) when the temperature is 294 kelvin. The party starts at 4:00 p.m., at which time, the temperature has risen to 305 kelvin. What is the new volume of the balloon? please help i will give brainliest.

Answer 1

Explanation:

the morning of the birthday party balloon filled with the 2.5 Litre of helium

temperature is 294kelvin

the party starts at the 4 p.m.

temperature rises 305 Kelvin.

the new volume = 4 litre.

At same temperature,

P

1

V

2

=P

2

V

2

(Boyle's law)

P

1

=10atm;P

2

=1atm

V

1

=4l=V

2

=8l

But while filling balloons from cylinder when pressure in cylinder becomes 1 atm then further filling is not possible (P

1

′

=9atm)

Let n be the number of balloons that can be filled.

∴P

1

′

V

1

=n(P

1

V

1

)

9×8=n(4×1)

n=

4

9×8

=18balloons