Answer:
Explanation:
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<span>2 C2H6(g) + 5 O2(g) --------> 4 CO(g) + 6 H2O(g)
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Avagadros constant states that 1 mol of any substance is made of 6.022 x 10^23 units.
These units could be atoms making up elements or molecules making up compounds.
1 mol of molecular oxygen (O2) is made of 6.022 x 10^23 molecules of O2
The mass of 1 mol of O2 is 32 g/mol
This means that the number of oxygen molecules in 32 g are 6.022 x 10^23 molecules
Therefore in 7.36 g of oxygen gas there are - 6.022 x 10^23 /32 g/mol x 7.36 g = 1.39 x 10^23 oxygen molecules
Answer is 1.39 x 10^23 oxygen molecules
The chemical reaction for this is:
2 C2H6 + 7 O2 => 4 CO2 + 6 H2O
Solving for CO2 with each reactant will give:
21.0 g C2H6 x (1 mol C2H6/30.08 g C2H6) x (6 mol H2O/2
mol C2H6) x (18 g H2O/1 mol H2O) = 37.70 g H2O
110 g O2 x (1 mol O2/32.00 g O2) x (6 mol CO2/7 mol O2) x
(18 g H2O/1 mol H2O) = 53.04 g H2O
Since the amount of H2O in C2H6 is lower therefore C2H6
is the limiting reactant and the maximum amount of water is only 38 g H2O (2 significant digits)
ANswer:
38 g water
Vegetative propagation is the right answer
