Answer:
The new temperature will be 2546 K or 2273 °C
Explanation:
Step 1: Data given
The initial temperature = 1000 °C =1273 K
The volume = 20L
The volume increases to 40 L
Step 2: Calculate the new temperature
V1/T1 = V2/T2
⇒with V1 = the initial volume = 20L
⇒with T1 = the initial temperature = 1273 K
⇒with V2 = the increased volume = 40L
⇒with T2 = the new temperature = TO BE DETERMINED
20L/ 1273 K = 40L / T2
T2 = 40L / (20L/1273K)
T2 = 2546 K
The new temperature will be 2546 K
This is 2546-273 = 2273 °C
Since the volume is doubled, the temperature is doubled as well
Answer:

Explanation:
Hello!
In this case, for the reaction:

In such a way, via the rate proportions, that is written considering the stoichiometric coefficients, we obtain:

Whereas the reactants, CO and H2 have negative stoichiometric coefficients; therefore the rate of disappearance of hydrogen gas is related to the rate of appearance of methanol as shown below:

Which means that the rate of disappearance of hydrogen gas is negative and the rate of appearance of methanol is positive.
Regards!
Answer: A. 11.15
Explanation:
The pH of a solution is given by the formular; pH = -log [H+].
pH = - log [ 7.0 x 10 ∧-12]
= 12 - log 7
= 12 - 0.845
= 11.15
The most appropriate and most commonly used metric when describing a person's mass is D.) kilograms
I hope this helped!! :))
Well you can freeze it to make it a solid then you can melt it to make it a liquid
I hope this helps you.