If the block is sliding at constant velocity then its speed is constant. That means it is not losing any kinetic energy. There is no friction acting and the coefficient of kinetic friction is zero. Sadly, that choice of answer is not offered.
Answer:
B temperature is an indirect measurement of the heat energy in a substance
Explanation:
The concept of temperature can be easily understood by looking at what happens when two objects are placed in contact with each other. By common experience, we know that the hotter object transfers heat energy to the colder object, until the two objects are in thermal equilibrium (= they have same temperature).
Thinking about the example above, we can say therefore that the temperature is an indirect measurement of the heat energy possessed by an object (or substance).
For a monoatomic gas, for instance, we define its internal energy as
where n is the number of moles, R is the gas constant, and T is the absolute temperature. From the formula, we see that the temperature is related to the internal energy of the gas, so measuring the temperature means indirectly measuring its internal energy.
According to motion in straight line t1≠t2
A biker travels d1 meters in t1 seconds at v1 m/s for the first leg and d2 meters in t2 seconds at v2 m/s for the second leg. It's possible that t1t2 if his average speed is equal to the average of v1 and v2.
An object is said to be in motion if its position in relation to its surroundings changes over time. It is a shift in an object's position over time. The only type of motion that exists is motion in a straight line.
A reference system is constantly used to describe a particle's motion. An arbitrary origin point is used to create a reference system, and a coordinate system is imagined to be connected to it. The reference system for a specific problem is the coordinate system that has been selected for it. For the majority of the problems, we typically select an earth-based coordinate system as the reference system.
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Answer:
d ≈ 7,6 g/cm³
Explanation:
d = m/V = 40g/5,27cm³ ≈ 7,6 g/cm³
V = l³ = (1.74cm)³ ≈ 5,27 cm³
Answer:
Magnitude of the average force exerted on the wall by the ball is 800N
Explanation:
Given
Contact Time = t = 0.05 seconds
Mass (of ball) = 0.80kg
Initial Velocity = u = 25m/s
Final Velocity = 25m/s
Magnitude of the average force exerted on the wall by the ball is given by;
F = ma
Where m = 0.8kg
a = Average Acceleration
a = (u + v)/t
a = (25 + 25)/0.05
a = 50/0.05
a = 1000m/s²
Average Force = Mass * Average Acceleration
Average Force = 0.8kg * 1000m/s²
Average Force = 800kgm/s²
Average Force = 800N
Hence, the magnitude of the average force exerted on the wall by the ball is 800N
