Amber has begun to cry when she is dropped off at daycare. This development likely occurred at what age? (2 points)

Physics

2 answers:

pychu [463]3 years ago

4 0

One year old (on average it would start at 7-9 months)

vovikov84 [41]3 years ago

3 0

I think it's one year old.

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a bicycle travels at a velocity of -2.33 m/s and has a displacement of -58.3 m. how much time did it take?

Alexandra [31]

We know that velocity is equal to the total displacement of an object over time.
$velocity = \frac{displacement}{time}$
Deriving from that equation, we can say that:
$t = \frac{d}{v}$
Okay, so here it goes:
$t = \frac{58.3m}{2.33 \frac{m}{s} } \\ t = 25.02s$
The bicycle took 25.02 seconds to displace at 58.3 meters.

5 0

2 years ago

Two balls are thrown against a wall. Ball 1 has a much higher speed than ball 2.

Sunny_sXe [5.5K]

Let both the balls have the same mass equals to m.

Let $v_1$ and $v_2$ be the speed of the ball1 and the ball2 respectively, such that

$v_1>v_2\;\cdots(i)$

Assuming that both the balls are at the same level with respect to the ground, so let h be the height from the ground.

The total energy of ball1= Kinetic energy of ball1 + Potential energy of ball1. The Kinetic energy of any object moving with speed, $v$ , is $\frac 12 m v^2$

and the potential energy is due to the change in height is $mgh$ [where $g$ is the acceleration due to gravity]

So, the total energy of ball1,

$=\frac 12 m v_1^2 + mgh\;\cdots(ii)$

and the total energy of ball1,

$=\frac 12 m v_2^2 + mgh\;\cdots(iii)$ .

Here, the potential energy for both the balls are the same, but the kinetic energy of the ball1 is higher the ball2 as the ball1 have the higher speed, refer equation (i)

So, $\frac 12 m v_1^2 >\frac 12 m v_2^2$

Now, from equations (ii) and (iii)

The total energy of ball1 hi higher than the total energy of ball2.

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2 years ago

Which formulas have been correctly rearranged to solve for radius? Check all that apply. r = GM central/v^2 r =fcm/v^2 r =ac/v^2

jek_recluse [69]

The orbital radius is: $r=\frac{GM}{v^2}$

Explanation:

The problem is asking to find the radius of the orbit of a satellite around a planet, given the orbital speed of the satellite.

For a satellite in orbit around a planet, the gravitational force provides the required centripetal force to keep it in circular motion, therefore we can write:

$\frac{GMm}{r^2}=m\frac{v^2}{r}$