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4 years ago

Amber has begun to cry when she is dropped off at daycare. This development likely occurred at what age? (2 points)

Physics

2 answers:

pychu [463]4 years ago

4 0

One year old (on average it would start at 7-9 months)

vovikov84 [41]4 years ago

3 0

I think it's one year old.

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Which of the following is true of an adiabatic process?

poizon [28]

Adiabatic process is that process in which heat of a closed system will remain conserved or we can say that system can not exchange its thermal energy from its surrounding

So here from 1st law of thermodynamics we can say

$\Delta Q = \Delta U + W$

since we know that

$\Delta Q = 0$

so we will have

$0 = \Delta U + W$

so we have

$-\Delta U = W$

so here correct answers are

<em>B. Heat is constant. </em>

7 0

3 years ago

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Speed of a train is 5m/s, find its value in km/hr.

antiseptic1488 [7]

Answer: 18km/hr

0.005km/s

1 sec --> 0.005

3600sec --> 0.005*3600 is 18

So, 18km/hr

4 0

2 years ago

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An alpha particle can be produced in certain radioactive decays of nuclei and consists of two protons and two neutrons. The part

Varvara68 [4.7K]

Answer:

Explanation:

charge, q = 2e = 2 x 1.6 x 10^-19 C = 3.2 x 10^-19 C

mass, m = 4 u = 4 x 1.661 x 10^-27 kg = 6.644 x 10^-27 kg

Radius, r = 4.5 cm = 0.045 m

Magnetic field, B = 1.20 T

(a) Let the speed is v.

$v=\frac{Bqr}{m}$

$v=\frac{1.20\times 3.2\times 10^{-19}\times 0.045}{6.644\times 10^{-27}}$

v = 2.6 x 10^6 m/s

(b) Let T be the period of revolution

$T=\frac{2\pi r}{v}$

$T=\frac{2\times 3.14\times 0.045}{2.6\times 10^{6}}$

T = 1.09 x 10^-7 s

$K=\frac{B^{2}\times q^{2}\times r^{2}}{2m}$

$K=\frac{\left ( 1.20\times 3.2 \times 10^{-19}\times 0.045 \right )^{2}}{2\times 6.644\times 10^{-27}}$

K = 2.25 x 10^-14 J

(d) Let the potential difference is V.

K = qV

$V = \frac{K}{q}$

$V= \frac{2.25\times 10^-14}{3.2\times 10^{-19}}$

V = 70312.5 V

5 0

3 years ago

The graph above represents an object moving with a __________________.

densk [106]

... cloak of invisibility spread over it.

3 0

3 years ago

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1. A car is traveling at 36 m/s hits a tree and comes to rest in 0.05 seconds.

QveST [7]

Answer: a. -720m/s^2

b. Yes, airbags will deploy

Explanation:

The formula for acceleration is:

= (Final velocity - Initial velocity)/Time

Final velocity = 0m/s

Initial velocity = 36m/s

Time taken = 0.05s

= (Final velocity - Initial velocity)/Time

= (0 - 36)/0.05

= -36/0.05

= -720m/s^2.

Since it's negative, it shows that there was a deceleration.

2. Yes the airbag will deploy since the acceleration gotten is more than -600 m/s^2.

3 0

4 years ago