Question

3/50 The standard test to determine the maximum lateral acceleration of a car is to drive it around a 200-ft-diameter circle painted on a level asphalt surface. The driver slowly increases the vehicle speed until he is no longer able to keep both wheel pairs straddling the line. If this maximum speed is 35 mi/hr for a 3000-lb car, determine its lateral acceleration capability an in g's and compute the magnitude F of the total friction force exerted by the pavement on the car tires.

Answer 1

Answer:

(a): Its lateral acceleration is ac= 8.02 m/s² = 0.81 * g

(b): The magnitude F of the friction force exerted by the paviment is F= 1091.28 N.

Explanation:

r= 100 ft = 30.48 m

Vt= 35 miles/hr = 15.64 m/s

m= 3000 lb = 136.07 kg

w= Vt/r

w= 0.5131 rad/s

ac= w² * r

ac= 8.02 m/s² = 0.818 * g  (a)

F= m * ac

F= 1091.28 N (b)