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Alona [7]
3 years ago
15

3/50 The standard test to determine the maximum lateral acceleration of a car is to drive it around a 200-ft-diameter circle pai

nted on a level asphalt surface. The driver slowly increases the vehicle speed until he is no longer able to keep both wheel pairs straddling the line. If this maximum speed is 35 mi/hr for a 3000-lb car, determine its lateral acceleration capability an in g's and compute the magnitude F of the total friction force exerted by the pavement on the car tires.
Physics
1 answer:
Delicious77 [7]3 years ago
5 0

Answer:

(a): Its lateral acceleration is ac= 8.02 m/s² = 0.81 * g

(b): The magnitude F of the friction force exerted by the paviment is F= 1091.28 N.

Explanation:

r= 100 ft = 30.48 m

Vt= 35 miles/hr = 15.64 m/s

m= 3000 lb = 136.07 kg

w= Vt/r

w= 0.5131 rad/s

ac= w² * r

ac= 8.02 m/s² = 0.818 * g  (a)

F= m * ac

F= 1091.28 N (b)

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Problem 21-40a:
Greeley [361]

Answer:

Part a)

\frac{F_e}{F_g} = 2.74 \times 10^{12}

Part b)

q = 3.37 \times 10^{-4} C

Explanation:

As we know that electric force on electric charge is given as

F = qE

here we have

q = 1.6 \times 10^{-19}C

E = 153 N/C

now force is given as

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F_g = mg

F_g = (9.1 \times 10^{-31})(9.81) = 8.93 \times 10^[-30} N

now the ratio of two forces is given as

\frac{F_e}{F_g} = \frac{2.45 \times 10^{-17}}{8.93 \times 10^{-30}}

\frac{F_e}{F_g} = 2.74 \times 10^{12}

Part b)

Now the ball is balanced by the electric force and the force of gravity on it

so here we have

F_g = qE

mg = qE

(5.25 \times 10^{-3})(9.81) = q(153)

here we have

q = 3.37 \times 10^{-4} C

8 0
3 years ago
Yasmin determines the velocity of a car to be 15m/s. The accepted value for the velocity of the car is 15.6m/s. What is yasmins
zaharov [31]

Percent error is calculated as follows:

% = ( |15-15.6| / 15.6 ) *  100%

% = (0.6/15.6) * 100%

% = 0.0385 * 100%

% = 3.85%

Hope this helped!

7 0
3 years ago
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If a stone is dropped from a height of 400 feet, its height after t seconds is given by s = 400 − 16t2. Find its instantaneous v
soldier1979 [14.2K]

Answer:

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Explanation:

given,

s = 400- 16 t²

we know,

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velocity an also be return as

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v= 0 -2\times 16 t

v = -32 t

Hence, instantaneous velocity function given by v = -32 t

To calculate instantaneous velocity, you need to insert value of time.

ex, instantaneous velocity at t = 4 s

       v = -32 x 4 = -128 m/s.

5 0
3 years ago
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Nikolay [14]
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3 years ago
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