Question

A 50.0 kg student climbs 5.00m up a rope at a constant speed. If the student's power output is 200.0 W, how long does it take the student to climb the rope ? How much work does the student do ?

Answer 1

Answer:

The time taken by the student to climb is 12.25 seconds and work done is 2450 J.            

Explanation:

Given that,

Mass of the student, m = 50 kg

The student climbs to a height of 5 meters at a constant speed.

The student's power output is 200.0 W, P = 200 W

The power of an object is given by work done divided by time taken. So,

$P=\dfrac{W}{t}$

(b) W is work done,

$W=mgh\\\\W=50\times 9.8\times 5\\\\W=2450\ J$

(b)

$t=\dfrac{W}{P}\\\\t=\dfrac{2450}{200}\\\\t=12.25\ s$

So, the time taken by the student to climb is 12.25 seconds and work done is 2450 J.