Explanation:
Let
are the number of turns in primary and secondary coil of the transformer such that,

A resistor R connected to the secondary dissipates a power 
For a transformer, 

...............(1)
The power dissipated through the secondary coil is :


.............(2)
Let
are the new number of turns in primary and secondary coil of the transformer such that,

New voltage is :

...............(3)
So, new power dissipated is 





So, the new power dissipated by the same resistor is 6400 watts. Hence, this is the required solution.
Answer:
Explanation:
It means that you only need apply 1/4th of the actual force required to operate the lever as you have an mechanical advantage which permits you to do 4 times the work with the same amount of effort.
When two or more waves combine to produce a new wave, that's 'interference'.
-- If the new wave has larger displacements (amplitude), then it's <em>CON</em>structive interference.
-- If the new wave has smaller displacements (amplitude), then it's DEstructive interference.
light
Explanation:
a computer has a screen and speakers, which produce light and siund