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Vesna [10]
3 years ago
8

Which group on the Periodic Table has at least

Chemistry
2 answers:
PIT_PIT [208]3 years ago
5 0
The correct option is GROUP 17.
The group 17 of the periodic table is made up of halogens. Halogens is the family name for fluorine, chlorine, bromine, iodine and all the other elements that are found in group 17. Some of the elements in this group are gases, some are liquids while others are solids.
PilotLPTM [1.2K]3 years ago
5 0

The group that has at least one element in each of the three phases of matter at STP is \boxed{\left( 3 \right){\text{ }}17}.

Further Explanation:

The systematic arrangement of various elements in the increasing order of their atomic numbers is termed as the periodic table. It exists in the form of a table, comprising of horizontal rows called periods and vertical columns called groups. There are 18 groups and 7 periods in a periodic table.

(1) Group 1 includes lithium, sodium, potassium, rubidium, cesium and francium. All of these elements are solids. So group 1 elements exist in only one phase of matter.

(2) Group 2 includes beryllium, magnesium, calcium, strontium, barium, and radium. All of these elements are solids. So group 2 elements exist in only one phase of matter.

(3) Group 17 includes fluorine, chlorine, bromine, iodine, and astatine. Out of these elements, F and Cl are gases, bromine is a liquid and iodine and astatine are solids at STP. So the elements of group 17 exist in different phases of matter.

(4) Group 18 includes helium, neon, argon, krypton, xenon, and radon. These are called noble gases as these are chemically inert. All the group 18 elements are gases in nature. So group 18 elements exist in only one phase of matter.

Learn more:

  1. Which general statement does not apply to metals? brainly.com/question/2474874
  2. Among sodium and chlorine, which has higher ionization energy? brainly.com/question/6324347

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Periodic classification of elements

Keywords: elements, group 1, group 2, group 18, group 17, solid, liquid, gas, phases of matter.

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Salt is poured from a container at 10 cm³ s-¹ and it formed a conical pile whose height at any time is 1/5 the radius of the abo
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Answer:

\displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}

Explanation:

Volume of a cone:

  • \displaystyle V=\frac{1}{3} \pi r^2 h

We have \displaystyle \frac{dV}{dt} = \frac{10 \ cm^3}{sec} and we want to find \displaystyle \frac{dh}{dt} \Biggr | _{h\ =\ 6}= \ ? when the height is 2 cm.

We can see in our equation for the volume of a cone that we have three variables: V, r, and h.

Since we only have dV/dt and dh/dt, we can rewrite the equation in terms of h only.

We are given that the height of the cone is 1/5 the radius at any given time, 1/5r, so we can write this as r = 5h.

Plug this value for r into the volume formula:

  • \displaystyle V =\frac{1}{3} \pi (5h)^2 h  
  • \displaystyle V =\frac{1}{3} \pi \ 25h^3

Differentiate this equation with respect to time t.

  • \displaystyle \frac{dV}{dt}  =\frac{25}{3} \pi \ 3h^2 \ \frac{dh}{dt}
  • \displaystyle \frac{dV}{dt}  =25 \pi h^2 \ \frac{dh}{dt}

Plug known values into the equation and solve for dh/dt.

  • \displaystyle 10 = 25 \pi (2)^2  \ \frac{dh}{dt}
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Divide both sides by 100π to solve for dh/dt.

  • \displaystyle \frac{10}{100 \pi} = \frac{dh}{dt}
  • \displaystyle \frac{dh}{dt} = \frac{1}{10 \pi}

The height of the cone is increasing at a rate of 1/10π cm per second.

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2 years ago
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A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is
liubo4ka [24]
The spacing is 14.4 nm (nanometers).
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Or : 1.512 * 10^(-3) mm
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