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2 years ago

8

Convert 225oC into Fahrenheit.

1 answer:

Ostrovityanka [42]2 years ago

5 0

437 is the answer for that

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Joaquin is at rest at the top of a hill on a skateboard. Four seconds later, he reaches the bottom of the hill at a final veloci

Andre45 [30]

Explanation:

Given: Initial Velocity=0

Final Velocity= 20 m/s

Time= 4 s

Accleration: Unknowns

Use kinematic equation

$v _{f} = v _{i} + at$

$20 = 0 + at$

$\frac{20m}{s} = a(4s)$

$a = \frac{5m}{ {s}^{2} }$

so a = 5 m/s^2

8 0

2 years ago

What is the output voltage from a step up transformer with 25 turns in the primary coil and 75 turns in the secondary coil if th

Greeley [361]

Answer:

360 V

Explanation:

We can use the transformer equation:

$\frac{V_p}{N_p}=\frac{V_s}{N_s}$

where

$V_p$ is the primary (input) voltage

$N_p$ is the number of turns in the primary coil

$V_s$ is the secondary (output) voltage

$N_s$ is the number of turns in the secondary coil

In this problem,

$V_p = 120 V\\N_p = 25\\N_s = 75$

Substituting into the equation, we can find the output voltage:

$V_s = N_s \frac{V_p}{N_p}=(75)\frac{120}{25}=360 V$

7 0

3 years ago

A hunter aims directly at a target (on the same level) 75m away. If the bullet leaves the gun at a speed of 180m/s, by what disp

rjkz [21]

Answer:

0.85 m

Explanation:

7 0

3 years ago

Answer the following question according to formal grammatical rules.

VARVARA [1.3K]

Answer:

c

Explanation:

just trying to follow basic grammar.

5 0

2 years ago

A 4.00 m long, massless beam rests horizontally on a support 3.00 m from the left

Rus_ich [418]

If the beam is in static equilibrium, meaning the Net Torque on it about the support is zero, the value of x₁ is 2.46m

Given the data in the question;

Length of the massless beam; $L = 4.00m$

Distance of support from the left end; $x = 3.00m$

First mass; $m1 = 31.3 kg$

Distance of beam from the left end( m₁ is attached to ); $x_1 = ?$

Second mass; $m_2 = 61.7 kg$

Distance of beam from the right of the support( m₂ is attached to ); $x_1 = 0.273m$

Now, since it is mentioned that the beam is in static equilibrium, the Net Torque on it about the support must be zero.

Hence, $m_1g( x-x_1) = m_2gx_2$

we divide both sides by $g$

$m_1( x-x_1) = m_2x_2$

Next, we make $x_1$ , the subject of the formula

$x_1 = x - [ \frac{m_2x_2}{m_1} ]$

We substitute in our given values

$x_1 = 3.00m - [ \frac{61.7kg\ * \ 0.273m}{31.3kg} ]$

$x_1 = 3.00m - 0.538m$

$x_1 = 2.46m$

Therefore, If the beam is in static equilibrium, meaning the Net Torque on it about the support is zero, the value of x₁ is 2.46m

Learn more; brainly.com/question/3882839

6 0

3 years ago