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2 years ago

In vehicles equipped with an anti-lock brake system

Physics

1 answer:

SOVA2 [1]2 years ago

6 0

Answer:

Yes

Explanation:

You can tell that your vehicle is equipped with an Anti-Lock Braking System (ABS) if it has a yellow ABS malfunction lamp on the instrument panel.

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A bungee jumper who is about to jump has her energy stored entirely as

Morgarella [4.7K]

Answer:

it will get slower and eventually she will stop jumping because there isnt enough force on the gravity causing her to go up and down

Explanation:

3 0

3 years ago

tester [92]

The pressure exerted on the block on the ground in N/m² is 200N/m².

<h3>What is pressure?</h3>

The pressure is the amount of force applied per unit area.

Given is a 5000 Newton block rests on the ground over 25 m² of area.

Pressure p = Force/Area

Put the values, we get

p = 5000 /25

p = 200 N/m²

Hence, pressure exerted on the block on the ground is 200 N/m².

Learn more about pressure.

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#SPJ1

4 0

2 years ago

A negatively-charged particle is slowly moving as it enters a region that has a constant magnetic field. If the velocity of the

Anna71 [15]

Answer:

no deflection and net force is zero. Moving in same direction and with same speed

Explanation:

Charge = negative

the angle between the velocity vector and the magnetic field vector is 0°, so the force is given by

F = q v B Sin 0

F = 0

As the force is zero so the charge particle moves with the same velocity and in the same direction.

there is no deflection in the path of negatively charged particle.

7 0

3 years ago

A car initially traveling at 27.2 m/s undergoes a constant negative acceleration of magnitude 1.90 m/s2 after its brakes are app

zubka84 [21]

Answer:

Therefore, the revolutions that each tire makes is:

$\Delta \theta=22\: rev$

Explanation:

We can use the following equation:

$\omega_{f}^{2}=\omega_{i}^{2}-2\alpha \Delta \theta$ (1)

The angular acceleration is:

$a_{tan}=\alpha R$

$\alpha=\frac{1.9}{0.325}$

$\alpha=5.85\: rad/s^{2}$

and the initial angular velocity is:

$\omega_{i}=\frac{v}{R}$

$\omega_{i}=\frac{27.2}{0.325}$

$\omega_{i}=83.69\: rad/s$

Now, using equation (1) we can find the revolutions of the tire.

$0=83.69^{2}-2*25.85 \Delta \theta$

$\Delta \theta=135.47\: rad$

Therefore, the revolutions that each tire makes is:

$\Delta \theta=22\: rev$

I hope it helps you!

6 0

3 years ago

What is the magnitude of the electric field strength between them, if the potential 7.95 cm from the zero volt plate (and 2.05 c

Dmitriy789 [7]

Answer:

ΔVab = Ed

ΔVab = Va-Vb = Va-V0 = Va

E = Va/ d

= 413V / 0.0795 m

= 5194.97 V/M

Explanation:

the potential difference between two uniform plates is calculated by the formula of electric field.

6 0

3 years ago