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Anit [1.1K]
3 years ago
11

A container of gas has a volume of 140.0 cm3 at a temperature of 27.0°C. If the

Chemistry
1 answer:
Vitek1552 [10]3 years ago
8 0

Answer:

285.185 (.185 repeating) cm^3

Explanation:

To get the answer, you divide 140 by 27 to get 5.185 (.185 repeating). Then, you multiply 5.185 (.185 repeating) by 55 and get 285.185 (.185 repeating) cm^3. Please use ^ next time to indicate exponents.

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What volume would 7.83 X 10^3 moles of Nitrogen gas occupy?
Kay [80]

Answer:

29.232 l

Explanation:

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7.83×10^23 mole of nitrogen =

22.4/(6.023×10^23)×7.83×10^23

=29.232 l

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What happened to the indivisible part of Dalton's atomic theory, and why?
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3 years ago
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aleksandr82 [10.1K]
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8 0
3 years ago
Read 2 more answers
How much concentrated solution would it take to prepare 2.90 L of 0.420 M HCl upon dilution with water
Zanzabum

Answer:

the quantity required can go from 117 ml (for maximum concentration) up to 2900 ml ( if the concentrated solution has molarity =0.420 M)

Explanation:

the amount of water required to dilute a solution V₁ liters of Molarity M₁ to V₂ liters of M₂

moles of hydrochloric acid =  M₁ * V₁= M₂ * V₂

V₁ =   V₂ * M₂/M₁

where

M₂ = 0.420 M

V₂ =2.90 L

Since the hydrochloric acid can be concentrated up to 38% p/V  ( higher concentrations are possible but the evaporation rate is so high that handling and storage require extra precautions, like cooling and pressurisation)

maximum M₁ =38% p/V = 38 gr/ 0.1 L / 36.5 gr/mol = 10.41 M

then

min V₁ =   V₂ * M₂/ max M₁ =  2.90 L* 0.420 M/ 10.41 M= 0.117 L = 117 ml

then the quantity required can go from 117 ml up to 2900 ml ( if M₁ = M₂)

5 0
3 years ago
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