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aev [14]
4 years ago
14

To analyze and design a passive, second-order bandpass filter using a series RLC circuit. A bandpass filter is needed for an equ

alizer, a device that allows one to select the level of amplification of sounds within a specific frequency band while not affecting the sounds outside that band. The filter should block frequencies lower than 1.8 kHz and have a resonant frequency of 5.4 kHz. A 3.2 μF capacitor and any needed resistors and inductors are available to be used in the filter. Design and analyze the RLC circuit that will make this bandpass filter.

Engineering
1 answer:
Likurg_2 [28]4 years ago
3 0

Answer:

The solution is attached in pictures below.

Explanation:

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Suppose the loop is moving toward the solenoid (to the right). Will current flow through the loop down the front, up the front,
Tems11 [23]

Answer:

See explanation

Explanation:

The magnetic force is

F = qvB sin θ

We see that sin θ = 1, since the angle between the velocity and the direction of the field is 90º. Entering the other given quantities yields

F

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6 0
3 years ago
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Assume that a p+ - n diode is built with an n region width l smaller than a hole diffusion length (l
RSB [31]

Answer: hiiiiii

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Explanation:

7 0
3 years ago
Pie charts should have no more than eight segments. True or False?
Pepsi [2]

Answer:

Explanation:

Pie charts generally should have no more than eight segments.

6 0
3 years ago
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Find the time-domain sinusoid for the following phasors:_________
sattari [20]

<u>Answer</u>:

a.  r(t) = 6.40 cos (ωt + 38.66°) units

b.  r(t) = 6.40 cos (ωt - 38.66°) units

c.  r(t) = 6.40 cos (ωt - 38.66°) units

d.  r(t) = 6.40 cos (ωt + 38.66°) units

<u>Explanation</u>:

To find the time-domain sinusoid for a phasor, given as a + bj, we follow the following steps:

(i) Convert the phasor to polar form. The polar form is written as;

r∠Ф

Where;

r = magnitude of the phasor = \sqrt{a^2 + b^2}

Ф = direction = tan⁻¹ (\frac{b}{a})

(ii) Use the magnitude (r) and direction (Φ) from the polar form to get the general form of the time-domain sinusoid (r(t)) as follows:

r(t) = r cos (ωt + Φ)

Where;

ω = angular frequency of the sinusoid

Φ = phase angle of the sinusoid

(a) 5 + j4

<em>(i) convert to polar form</em>

r = \sqrt{5^2 + 4^2}

r = \sqrt{25 + 16}

r = \sqrt{41}

r = 6.40

Φ = tan⁻¹ (\frac{4}{5})

Φ = tan⁻¹ (0.8)

Φ = 38.66°

5 + j4 = 6.40∠38.66°

(ii) <em>Use the magnitude (r) and direction (Φ) from the polar form to get the general form of the time-domain sinusoid</em>

r(t) = 6.40 cos (ωt + 38.66°)

(b) 5 - j4

<em>(i) convert to polar form</em>

r = \sqrt{5^2 + (-4)^2}

r = \sqrt{25 + 16}

r = \sqrt{41}

r = 6.40

Φ = tan⁻¹ (\frac{-4}{5})

Φ = tan⁻¹ (-0.8)

Φ = -38.66°

5 - j4 = 6.40∠-38.66°

(ii) <em>Use the magnitude (r) and direction (Φ) from the polar form to get the general form of the time-domain sinusoid</em>

r(t) = 6.40 cos (ωt - 38.66°)

(c) -5 + j4

<em>(i) convert to polar form</em>

r = \sqrt{(-5)^2 + 4^2}

r = \sqrt{25 + 16}

r = \sqrt{41}

r = 6.40

Φ = tan⁻¹ (\frac{4}{-5})

Φ = tan⁻¹ (-0.8)

Φ = -38.66°

-5 + j4 = 6.40∠-38.66°

(ii) <em>Use the magnitude (r) and direction (Φ) from the polar form to get the general form of the time-domain sinusoid</em>

r(t) = 6.40 cos (ωt - 38.66°)

(d) -5 - j4

<em>(i) convert to polar form</em>

r = \sqrt{(-5)^2 + (-4)^2}

r = \sqrt{25 + 16}

r = \sqrt{41}

r = 6.40

Φ = tan⁻¹ (\frac{-4}{-5})

Φ = tan⁻¹ (0.8)

Φ = 38.66°

-5 - j4 = 6.40∠38.66°

(ii) <em>Use the magnitude (r) and direction (Φ) from the polar form to get the general form of the time-domain sinusoid</em>

r(t) = 6.40 cos (ωt + 38.66°)

3 0
3 years ago
Fibonacci sequence has many applications in Computer Science. Write a program to generate Fibonacci numbers as many as desired.
VikaD [51]

Answer:

The Python Code for Fibonacci Sequence is :

# Function for nth Fibonacci number  

def Fibonacci(n):  

if n<0:  

 print("Incorrect input")  

# First Fibonacci number is 0  

elif n==0:  

 return 0

# Second Fibonacci number is 1  

elif n==1:  

 return 1

else:  

 return Fibonacci(n-1)+Fibonacci(n-2)  

# Driver Program  

print(Fibonacci(9))  

Explanation:

The Fibonacci numbers are the numbers in the following integer sequence.

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, ……..

In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the recurrence relation

Fn = Fn-1 + Fn-2

with seed values

F0 = 0 and F1 = 1.

8 0
3 years ago
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