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3 years ago

List five things the welding symbol will tell the welder about the weld that is to be made.

Engineering

1 answer:

alexgriva [62]3 years ago

7 0

Answer:

depth

rod to use

travel speed

type of weld

tthe side to be welded on

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4 years ago

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The conditions at the beginning of compression in an Otto engine operating on hot-air standard with k=1.35 and 101.325 kPa, 0.05

Katyanochek1 [597]

Answer:

$P_m=181.42 KPa$

Explanation:

$P_1=101.325 KPa,V_1=0.05m^3,T_1=32C$ ,K=1.35

Clearance is 8%.

Heat added=15 KJ

We know that compression ratio $r=1+\dfrac{1}{C}$

$r=1+\dfrac{1}{0.08}$

r=13.5

$r=\dfrac{V_1}{V_2}$

$13.5=\dfrac{0.05}{V_2}$

$V_2=3.7\times 10^{-3}$

We know that efficiency of otto cycle

$\eta =1-\dfrac{1}{r^{k-1}}$

$\eta =1-\dfrac{1}{13.5^{1.35-1}}$

$\eta =0.56$

$\eta =\dfrac{W}{Q}$

W is the work out put and Q is the heat addition.

$0.56 =\dfrac{W}{15}$

W=8.4 KJ

We know that Work =Mean effective pressure x swept volume.

Here swept volume $V_s=V_1-V_2$

$V_s=0.05-3.7\times 10^{-3}$

$V_s=0.0463 m^3$

Noe by putting the values

Work =Mean effective pressure x swept volume.

$8.4=P_m\times 0.0463$

$P_m=181.42 KPa$

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3 years ago

Design a logic circuit that has a 4-bit binary number as an input and one output. The output should be 1 iffthe input is a prime

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Answer:

Check the explanation

Explanation:

Solution

Let the $L_1$ binary input one A,B,C,D and output is F with $L_1$ binary inputs we have $16=2^4$ combination as in below.

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4 years ago

Carbon dioxide at 20°C flows in a pipe at a rate of 0.005 kg/s. Determine the minimum diameter required if the flow is laminar (

Vesna [10]

Answer:

the required diameter is 0.344 m

Explanation:

given data:

flow is laminar

flow of carbon dioxide Q = 0.005 Kg/s

for flow to be laminar, Reynold's number must be less than 2300 for pipe flow and it is given as

$\frac{\rho VD}{\mu }$

arrange above equation for diameter

\frac{\rho Q D}{\mu A }<2300

dynamic density of carbon dioxide = 1.47× $10^{-5}$ Pa sec

density of carbon dioxide is 1.83 kg/m³

$\frac{1.83\times 0.0056\times D}{1.47\times 10^{-5}\times \frac{\pi}{4} \times D^{2} }$

$\frac{1.83\times 0.0056}{1.47\times 10^{-5}\times \frac{\pi}{4} \times 2300}= D$

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3 years ago

Why are the main cables of the Golden Gate Bridge made of numerous smaller cables?

Hunter-Best [27]

Answer:

The main cables of the Golden Gate Bridge are made of numerous smaller cables because by combining several thousand in number of smaller cables, each having a diameter which is approximately the diameter of a pencil, into the required cable diameter dimensions, the flexibility, strength, resistance to cracking, rotation resistance, crushing resistance and fatigue resistance of the main cables are increased, and failure of a few strands in a multi-stranded cable is more likely to be detected before catastrophic failure takes place than in a single cable

The properties of strength and flexibility that the cable provides are required so that the bridge can better cushion the seismic turbulence of the water and strong wind energy at the bay of San Francisco, the location of the bridge

Explanation:

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3 years ago

List five things the welding symbol will tell the welder about the weld that is to be made.​

List five things the welding symbol will tell the welder about the weld that is to be made.