Weaken London dispersion forces and stronger dipole dipole forces
Answer:
C₅H₁₁Cl
Explanation:
Count all the carbon, hydrogen, and chlorine atoms. The number of atoms of each element is the subscript for each element in the formula. No subscript is understood to be one. Carbon goes first, hydrogen goes second, and chlorine goes last when writing the formula.
A) 7.5 % m / V
7.5 g -------- 100 mL ( solution )
mass g ------ 45.0 mL
mass g = 45.0 x 7.5 / 100
mass g = 337.5 / 100 => 3.375 g
1 mole KCl -------------- 74.55 g
moles KCl ---------------- 3.375 g
moles KCl = 3.375 x 1 / 74.55 => 0.0452 moles of KCl
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b) 9.5 % ( m / V ) :
9.5 g -------- 100 mL ( solution )
mass g ------ 400.0 mL
mass g = 400.0 x 9.5 / 100
mass g = 3800 / 100 => 38 g
1 mole acetic acid -------------- 60.05 g
moles acetid acid ---------------- 38 g
moles acetid acid = 38 x 1 / 60.05 => 0.6328 moles of acetid acid<span>
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hope this helps!
1 mol N₂ - 2 mol NH₃
6 mol N₂ - x mol NH₃
x=2×6/1=12 mol
12 mol NH₃
