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Hunter-Best [27]
3 years ago
13

If hot air rises then why is it cold in space please explain in detail thank you

Physics
2 answers:
7nadin3 [17]3 years ago
7 0
Hot air doesn’t rise, its displaced by colder air because it is less dense. Also, space doesn’t exactly have a temperature. The gases are cold, especially the farther you are away from stars, planets and other objects.
Helen [10]3 years ago
5 0
Hot air has a lower density than the surrounding atmosphere, therefore,it will rise.. The reason it is "cold" in the upper atmosphere is actually because of a lower air density.
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Which states of matter are significantly compressible?
andreev551 [17]
Hello.


The gaseous state is the more compressible state, because it has the volume of its container.

The liquid state is virtually incompressible, and the solid state compression is very small.

The plasma is another state that has high compression, but in this case the matter is not bound(we don't have the proton in the core of the atom)
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3 years ago
The mass of a string is 7.7 × 10-3 kg, and it is stretched so that the tension in it is 190 N. A transverse wave traveling on th
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Length of the strings = 2.33 m

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2 years ago
In a neutral atom the number of electrons equals the number of what part of what other part
koban [17]

Protons

Explanation:

In a neutral atom, the number of electrons equals the number of protons in the atom.

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In a neutral atom, the number of protons and electrons must be the same.

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Learn more:

Cations brainly.com/question/8698247

#learnwithBrainly

3 0
3 years ago
Two cylindrical rods, one copper and the other iron, are identical in lengths and cross-sectional areas. They are joined, end to
Pie

Answer:

Vc = 2.41 v

Explanation:

voltage (v) = 16 v

find the voltage between the ends of the copper rods .

applying the voltage divider theorem

Vc = V x (\frac{Rc}{Rc + Ri})

where

  • Rc = resistance of copper = \frac{ρl}{a}  (l = length , a = area, ρ = resistivity of copper)
  • Ri = resistance of iron = \frac{ρ₀l}{a}  (l = length , a = area, ρ₀ = resistivity of copper)

Vc =  V x (\frac{\frac{ρl}{a}}{\frac{ρl}{a} + \frac{ρ₀l}{a}})

Vc = V x (\frac{ρ x (\frac{l}{a})}{(ρ + ρ₀) x (\frac{l}{a})})

Vc = V x (\frac{ρ}{ρ + ρ₀})

where

  • ρ = resistivity of copper = 1.72 x 10^{-8} ohm.meter
  • ρ₀ = resistivity of iron = 9.71 x 10^{-8} ohm.meter

Vc = 16 x (\frac{1.72 x 10^{-8}}{1.72 x 10^{-8} + 9.71 x 10^{-8}})

Vc = 2.41 v

5 0
3 years ago
PLEASE HELP!!!
Simora [160]
I only know what number 1. is and its Mechanical Energy.
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3 years ago
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