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Mrac [35]
3 years ago
12

Sound travels fastest in _____.

Physics
2 answers:
Irina-Kira [14]3 years ago
6 0
Sound travels  fastest in solids,than liquids, and  faster in liquids, than in gases.
Charra [1.4K]3 years ago
4 0

Answer:

Sound travels fastest in solids

Explanation:

Sound is a type of mechanical waves. Mechanical waves are produced by the oscillations of the particles in the medium the wave is travelling through.

The speed of a mechanical wave depends on the density of the medium: the higher the density, the higher the speed. This is because in a medium with higher density, atoms/molecules are closer together, so they collide more frequently and therefore the wave can be transmitted faster and more efficiently.

Since solids have higher density than liquids and gases, this also means that mechanical waves (so, sound as well) travel faster in solids than liquids or gases.

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Earning Goal: To be able to calculate work done by a constant force directed at different angles relative to displacement
lana [24]

Answer:

the work done by the 30N force is 4156.92 J.

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3 years ago
A transformer has two sets of coils, the primary with N1 = 160 turns and the secondary with N2 = 1400 turns. The input rms volta
vovikov84 [41]

To solve the problem it is necessary to apply the concepts related to the voltage in a coil, through the percentage relationship that exists between the voltage and the number of turns it has.

So things our data are given by

N_1 = 160

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PART A) Since it is a system in equilibrium the relationship between the two transformers would be given by

\frac{N_1}{N_2} = \frac{\Delta V_{1rms}}{\Delta V_{2rms}}

So the voltage for transformer 2 would be given by,

\Delta V_{2rms} = \frac{N_2}{N_1} \Delta V_{1rms}

PART B) To express the number value we proceed to replace with the previously given values, that is to say

\Delta V_{2rms} = \frac{N_1}{N_2} \Delta V_{1rms}

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7 0
3 years ago
An electron with charge −e and mass m moves in a circular orbit of radius r around a nucleus of charge Ze, where Z is the atomic
shepuryov [24]

Answer:

v=\sqrt{\frac{kZe^2}{mr}}

Explanation:

The electrostatic attraction between the nucleus and the electron is given by:

F=k\frac{(e)(Ze)}{r^2}=k\frac{Ze^2}{r^2} (1)

where

k is the Coulomb's constant

Ze is the charge of the nucleus

e is the charge of the electron

r is the distance between the electron and the nucleus

This electrostatic attraction provides the centripetal force that keeps the electron in circular motion, which is given by:

F=m\frac{v^2}{r} (2)

where

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v is the speed of the electron

Combining the two equations (1) and (2), we find

k\frac{Ze^2}{r^2}=m\frac{v^2}{r}

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