Upward force provided by the branch is 260 N
<u>Explanation:</u>
Given -
Mass of Gibbon, m = 9.3 kg
Length of the branch, r = 0.6 m
Speed of the movement, v = 3.3 m/s
Upward force, T = ?
The tension force in the rod must be greater than the weight at the bottom of the swing in order to provide an upward centripetal acceleration.
Therefore,
F net = T - mg
F net = ma = mv²/r
Thus,
T = mv²/r + mg
T = m ( v²/r + g)
T = 9.3 [ ( 3.3)² / 0.6 + 9.8]
T = 259.9 N ≈ 260 N
Therefore, upward force provided by the branch is 260 N
F=MA - equation
F=(0.25 kg)(15.5 m/s^2) - multiply the mass and the acceleration
F= 3.875 N - N means Newton (SI unit for force)
Hope this helps
It would float outward as all space is expanding from the center constantly. of by some chance it for caught in the orbit of another celestial body with huge mass it may orbit that, bur other wise it would just push outward from the center of the universe theoretically the big bang
Kinetic energy since if its rolling is already using the stored potential energy that it had before it was given an amount of energy to release it for a given time
Answer:
The radius of the sphere is 4.05 m
Explanation:
Given;
potential at surface, 
= 450 V
potential at radial distance, 
= 150
radial distance, l = 8.1 m
Apply Coulomb's law of electrostatic force;
Therefore, the radius of the sphere is 4.05 m
