PLEASE HELP!!! ILL GIVE BRANLIEST *EXTRA POINTS* dont skip :((
2 answers:
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Complete question:
A structural component in the form of a wide plate is to be fabricated from a steel alloy that has a plane strain fracture toughness of 98.9 MPa root m (90 ksi root in.) and a yield strength of 860 MPa (125,000 psi). The flaw size resolution limit of the flaw detection apparatus is 3.0 mm (0.12 in.). If the design stress is one-half of the yield strength and the value of Y is 1.0, determine whether or not a critical flaw for this plate is subject to detection.
Answer:
Since the flaw 17mm is greater than 3 mm the critical flaw for this plate is subject to detection
so that critical flow is subject to detection
Explanation:
We are given:
Plane strain fracture toughness K
Yield strength Y = 860 MPa
Flaw detection apparatus = 3.0mm (12in)
y = 1.0
Let's use the expression:
We already know
K= design
a = length of surface creak
Since we are to find the length of surface creak, we will make "a" subject of the formula in the expression above.
Therefore
Substituting figures in the expression above, we have:
= 0.0168 m
= 17mm
Therefore, since the flaw 17mm > 3 mm the critical flow is subject to detection
Answer:
#include<stdio.h>
#include<math.h>
void output_amortized(float loan_amount,float intrest_rate,int term_years)
{
int i,j; //Month
int payments; //Number of payments
float loanAmount; //Loan amount
float anIntRate; //Yealy interest Rate
float monIntRate; //Monthly interest rate
float monthPayment; //Monthly payment
float balance; //Balance due
float monthPrinciple; //Monthly principle paid
float monthPaidInt; //Month interest paid
balance=loan_amount;
//Calculations
//Monthly interest rate
monIntRate = ((intrest_rate/(100*12)));
//Monthly payment
payments=term_years;
monthPayment = (loan_amount * monIntRate * (pow(1+monIntRate, payments)/(pow (1+monIntRate, payments)-1)));
monthPaidInt = balance * monIntRate;
//Amount paid to principle
monthPrinciple = monthPayment-monthPaidInt;
//New balance due
balance = balance - monthPrinciple;
printf("\n\nMonthly payment should be :%.2f\n\n",monthPayment);
printf("============================AMORTIZATION SCHEDUAL==========================\n");
printf("#\tPayment\t\tIntrest\t\tPrinciple\t\tBalance\n");
for(i=0;i<payments;i++)
{
printf("%d%9c%.2f%9c%.2f%16c%.2f%14c%.2f\n",(i+1),'$',monthPayment,'$',monthPaidInt,'$',monthPrinciple,'$',balance);
monthPaidInt = balance * monIntRate;
//Amount paid to principle
monthPrinciple = monthPayment-monthPaidInt;
//New balance due
balance = balance - monthPrinciple;
}
}
int main()
{
float principle,rate;
int termYear;
printf("Enter the loan amount: $");
scanf("%f",&principle);
printf("Enter the intrest rate :%");
scanf("%f",&rate);
printf("Enter the loan duration in years: ");
scanf("%d",&termYear);
output_amortized(principle,rate,termYear);
}
Explanation:
see output
