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Vadim26 [7]
3 years ago
5

The picture above shows 3 sets of balloons, all with a particular charge. Which of the picture(s) is true? Explain. Then explain

why the other 2 pictures are incorrect. Make sure to explain all 3 sets.

Physics
2 answers:
IrinaVladis [17]3 years ago
8 0
Among all of the others Picture 3 is correct.

We know, Like charges repel each other whereas unlike charges attract each other, In picture 3 they are like charges (both are positive) so, we can repulsion hence, picture is correct!

In picture 1, they are unlike charges, & showing repulsion which is wrong, same In picture 2, they are like charges & showing attraction so they are wrong as well

Hope this helps!
MariettaO [177]3 years ago
7 0
C is correct because they would repel each other A is wrong be they wouldn't repel And B is wrong because they shouldn't be repelling each other
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A car traveled 1,215 km West from El Paso to Dallas in 13.5 hours. What was its velocity?
Mariana [72]
............The answer is B
3 0
3 years ago
ASAP if you answer right I will mark brainiest....
rjkz [21]

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Explanation: Hope this helped :)

8 0
3 years ago
Find the magnitude and direction of a force between a 25.0 coulomb charge and a 40.0coulomb charge when they are separated by a
deff fn [24]

Answer:

95.0 colomb

Explanation:

Make sure to understand the concept

6 0
3 years ago
Helpp pls
Kipish [7]

Answer:

The intensity of the electric field is

|E|=10654.37 \:N/C

Explanation:

The electric field equation is given by:

|E|=k\frac{q}{d^{2}}

Where:

  • k is the Coulomb constant
  • q is the charge at 0.4100 m from the balloon
  • d is the distance from the charge to the balloon

As we need to find the electric field at the location of the balloon, we just need the charge equal to 1.99*10⁻⁷ C.

Then, let's use the equation written above.

|E|=(9*10^{9})\frac{1.99*10^{-7}}{0.41^{2}}

|E|=10654.37 \:N/C

I hope it helps you!

5 0
3 years ago
Using energy considerations, calculate the average force (in N) a 67.0 kg sprinter exerts backward on the track to accelerate fr
Illusion [34]

Answer:

F_{sprinter}=110.4N

Explanation:

Given data

Mass m=67.0 kg

Final Speed vf=8.00 m/s

Initial Speed vi=2.00 m/s

Distance d=25.0 m

Force F=30.0 N

From work-energy theorem we know that the work done equals the change in kinetic energy

W=ΔK=Kf-Ki=1/2mvf²-1/2mvi²

And

W=F_{total}.d

So

W=1/2mv_{f}^2-1/2mv_{i}^2\\F_{total}=\frac{1/2mv_{f}^2-1/2mv_{i}^2}{d} \\F_{total}=\frac{1/2(67.0kg)(8.00m/s)^2-1/2(67.0kg)(2.00m/s)^2}{25.0m} \\F_{total}=80.4N

and we know that the force the sprinter exerted Fsprinter the force of the headwind Fwind=30.0N

So

F_{sprinter}=F_{total}+F_{wind}\\F_{sprinter}=80.4N+30N\\F_{sprinter}=110.4N  

7 0
3 years ago
Read 2 more answers
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