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Ivanshal [37]
3 years ago
13

A 15-kg ball is tossed up into the air. The ball is 2 meters off the ground traveling 4 m/s. What is the potential energy? A. 29

4 J B. 120 J C. 414 J D. 0
Physics
1 answer:
Sladkaya [172]3 years ago
7 0

Answer: 0j

Explanation:

At that point potential energy is zero and kinetic energy is maximum.. P. E=mgh=0

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A helicopter (m = 3250 kg) is cruising at a speed of 56.9 m/s atan altitude of 185 m. What is the total mechanical energy of the
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Answer:

The mechanical energy of the helicopter is 1.12\times 10^7\ J.

Explanation:

It is given that,

Mass of the helicopter, m = 3250 kg

Speed of the helicopter, v = 56.9 m/s

Position of the helicopter, h = 185 m

The energy possessed by an object due to its motion is called its kinetic energy. It is given by :

E=\dfrac{1}{2}mv^2

E=\dfrac{1}{2}\times 3250\times (56.9)^2  

E=5.26\times 10^6\ J

The energy possessed by an object due to its position is called its potential energy. It is given by :

E=mgh

E=3250\times 9.8\times 185  

E=5.89\times 10^6\ J

The sum of kinetic and potential energy is called mechanical energy of the system. It is given by :

M=5.26\times 10^6+5.89\times 10^6

M=11.15\times 10^6\ J

or

M=1.12\times 10^7\ J

So, the mechanical energy of the helicopter is 1.12\times 10^7\ J. Hence, this is the required solution.

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3 years ago
What happens to light when it passes through a lens?
Novay_Z [31]
B. Light refracts as it passes through a lens.

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A truck covers 40.0 m in 7.50 s while uniformly slowing down to a final velocity of 2.55 m/s. (a) Find the truck's original spee
iris [78.8K]

Answer:

(a) 8.117 (b) 0.742m/sec^2

Explanation:

We have given distance s =40 m time t=7.5 sec

Final velocity v =2.55 m/sec

From the first equation of motion v=u-at (negative sign because there is retrdation as the truck speed is slowing down )

So 2.55=u-7.5a --------------eqn 1

From the second equation of motion s=ut-\frac{1}{2}at^2 ( negative sign because there is retrdation as the truck speed is slowing down )

So 40=7.5u-0.5\times a\times 7.5^2

40=7.5u-28.125a------------------eqn 2

On solving eqn1 and eqn 2

u=8.117 m/sec and a=-0.742m/sec^2

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I think it’ll be a or d
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