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Serhud [2]
4 years ago
10

A bike rider pedals with constant acceleration to reach a velocity of 7.5 (vf)m/s over a time of 4.5 s(t). during the period of

acceleration, the bike's displacement is 19 m(d). what was the initial velocity of the bike?
Physics
1 answer:
BigorU [14]4 years ago
6 0
<span>The initial velocity of the bike was 1.67 (vf)m/s. This is found by evaluating 7.5/4.5 which yields the velocity per unit of time which is equivalent to initial velocity.</span>
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Identify two structural characteristics specific to muscle tissue.
Semmy [17]

Answer:

Explanation:

Muscle cells are excitable; they respond to a stimulus.meaning they can shorten and generate a pulling force. When attached between two movable objects, such as two bones, contraction of the muscles cause the bones to move.It contains protein fibers which contract to make the cell shorter.

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65. A length of wire is bent into a closed loop and a magnet is plunged into it, inducing a voltage and, consequently, a current
natulia [17]

Answer:

Resistance of the second wire is twice the first wire.

Explanation:

Let us first see the formula of resistance;

R = pxL/A

Here L is the lenght of the wire, A the area and p is the resistivity of wire.

As we are given that the length of second wire is double than that of the first wire, hence the resistance of second wire would be double.

Since we have two loop in second case, inducing double voltage but as resistance is doubled so the current would remain same according to ohms law

I = V/R

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3 years ago
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a missile is moving 1810 m/s at a 20.0 degree angle. it needs to hit a target 19,500 m away in a 32.0 degree direction in 9.20 s
Ket [755]

Answer:

112 m/s², 79.1°

Explanation:

In the x direction, given:

x₀ = 0 m

x = 19,500 cos 32.0° m

v₀ = 1810 cos 20.0° m/s

t = 9.20 s

Find: a

x = x₀ + v₀ t + ½ at²

19,500 cos 32.0° = 0 + (1810 cos 20.0°) (9.20) + ½ a (9.20)²

a = 21.01 m/s²

In the y direction, given:

y₀ = 0 m

y = 19,500 sin 32.0° m

v₀ = 1810 sin 20.0° m/s

t = 9.20 s

Find: a

y = y₀ + v₀ t + ½ at²

19,500 sin 32.0° = 0 + (1810 sin 20.0°) (9.20) + ½ a (9.20)²

a = 109.6 m/s²

The magnitude of the acceleration is:

a² = ax² + ay²

a² = (21.01)² + (109.6)²

a = 112 m/s²

And the direction is:

θ = atan(ay / ax)

θ = atan(109.6 / 21.01)

θ = 79.1°

5 0
3 years ago
I need help me with my question
lisov135 [29]

The tilt of the moon's axis does not allow for monthly alignment, so the lunar and solar eclipse do not happen every month.

<h3>How do the lunar and solar eclipse occur?</h3>
  • For the occurrence of lunar and solar eclipse, the sun, moon and the earth must remain in a plan and along a straight line.
  • When the earth appears in between the sun and the moon, lunar eclipse occurs.
  • When the moon appears in between the sun and the earth, solar eclipse occurs.
  • The moon and earth are rotating not only around the sun, but also around the black hole of Milky way galaxy.
  • So they are not present in a plan as well as in a straight line in every full moon and new moon time.

Thus, we can conclude that the option D is correct.

Learn more about the lunar eclipse and solar eclipse here:

brainly.com/question/8643

#SPJ1

4 0
2 years ago
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