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Serhud [2]
3 years ago
10

A bike rider pedals with constant acceleration to reach a velocity of 7.5 (vf)m/s over a time of 4.5 s(t). during the period of

acceleration, the bike's displacement is 19 m(d). what was the initial velocity of the bike?
Physics
1 answer:
BigorU [14]3 years ago
6 0
<span>The initial velocity of the bike was 1.67 (vf)m/s. This is found by evaluating 7.5/4.5 which yields the velocity per unit of time which is equivalent to initial velocity.</span>
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Answer:

C. 1500.

Explanation:

750 / .5 = 1500.

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Answer:

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Answer:

= 4.38 × 10³⁴kgm²/s

Explanation:

Given that,

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7 0
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2 years ago
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Answer:

T =176 N

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T = m_2(g +a)

T = 4(9.81+34.2)

T =176 N

7 0
3 years ago
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