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3 years ago

What is the term that describes waves that require a medium through which to travel?

Physics

1 answer:

gladu [14]3 years ago

8 0

Answer:

Mechanical waves are waves that require a medium. This means that they have to have some sort of matter to travel through. These waves travel when molecules in the medium collide with each other passing on energy. One example of a mechanical wave is sound.

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A man stands at the midpoint between two speakers that are broadcasting an amplified static hiss uniformly in all directions. Th

LiRa [457]

Answer:

A) total intensity = 5x10^-4W/m2

B) total intensity = 5.34x10^-4W/m2

Explanation:

Detailed explanation and calculation is shown in the image below

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3 years ago

Which of the following is not part of a circuit? film Load Key Cell

qaws [65]

Explanation:

I believe film is not part of a circuit

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3 years ago

What is the half-life of isotope X?

Brrunno [24]

Answer:

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3 years ago

Read 2 more answers

You have just landed on Planet X. You release a 100-g ball from rest from a height of 10.0 m and measure that it takes 3.40 s to

Nana76 [90]

Answer:

w = 0.173 N

Explanation:

The weigh of any object is computed by multiplying its mass to the acceleration of gravity, so we need to find the gravity on that planet in order to compute the weigh we want.

The ball has a mass of 0.1 kg and its released from a height of 10 m, therefore it is in a free fall motion with gravity acting as a constant acceleration on the body, we can use the equations for free fall movement in order to determine the value for this acceleration:

y(t) = v_0 * t + y_0 - 0.5 * g * t^2

y(t) is the position in the end of the movement, when t = 3.4 s, so y(t) = 0 m.

v_0 is the initial velocity, in this case v_0 = 0 m/s.

y_0 is the initial position of the ball, in this case it is 10 m.

g is the gravity that we want to know.

Applying these values in the equation we have:

0 = 0*(3.4) + 10 - 0.5*g*(3.4)^2

0 = 10 - 0.5*11.56*g

0 = 10 -5.78*g

5.78*g = 10

g = 1.73 m/s^2

Then we can use this value to find out the weigh of the ball in that planet:

w = g*m = 0.1*1.73 = 0.173 N

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4 years ago

Consider light energy that is momentarily absorbed in glass and then re-emitted. Compared to the absorbed light, the frequency o

fredd [130]

The frequency of the re-emitted light is identical to that of the absorbed light.

To find the answer, we need to know more about the frequency of light.

<h3> Why the re-emitted light has the same frequency?</h3>

The wavelength of the light that is momentarily absorbed in glass and then re-emitted is the same, which explains why the re-emitted light has the same frequency as the absorbed light and the frequency of the absorbed light is the same.
An electromagnetic wave's energy is inversely related to its frequency.
The relationship between the wave's wavelength and frequency depends on the speed of light:

$frequency=\frac{c}{wave length}$ , c is the speed of light.

Despite not having mass, light still has energy, and that energy is conserved.
As a result, in order for there to be energy conservation, the energy of the light that is received and reemitted must be equal.

Thus, we can conclude that, the re-emitted light's frequency matches the absorbed light's frequency.

Learn more about frequency here:

brainly.com/question/26754018

#SPJ4

4 0

1 year ago