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Mashcka [7]
3 years ago
9

What is the term that describes waves that require a medium through which to travel?

Physics
1 answer:
gladu [14]3 years ago
8 0

Answer:

Mechanical waves are waves that require a medium. This means that they have to have some sort of matter to travel through. These waves travel when molecules in the medium collide with each other passing on energy. One example of a mechanical wave is sound.

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A supersonic aircraft flies at 3 km altitude at a speed of 1000 m/s on a standard day. How long after passing directly above a g
Gre4nikov [31]

Answer:

<h3>After 3seconds</h3>

Explanation:

A supersonic aircraft flies at 3 km altitude at a speed of 1000 m/s on a standard day. How long after passing directly above a ground observer is the sound of the aircraft heard by the ground observer

Using the formula for calculating speed expressed as;

Speed = Distance/Time

Given;

Distance = 3km = 3000m

Speed = 1000m/s

Required

How long after passing directly above a ground observer is the sound of the aircraft heard by the ground observer (Time)

From the formula;

Time = Distance/speed

Time = 3000/1000

Time = 3seconds

Hence the sound of the aircraft is heard after 3 seconds

7 0
3 years ago
The correct order of the planets is:
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A window has a glass surface of 2907 cm2 and a thickness of 5.6 mm. Find the rate of energy transfer by conduction through this
butalik [34]

Answer:

2.30714 W

-16.38071 W

Explanation:

k = Heat conduction coefficient = 0.8 W/(m·°C)

A = Area = 2907 cm²

l = Thickness = 5.6 mm

T_2 = Outside temperature

T_1 = Inside temperature

Rate of heat transfer is given by

Q=\frac{kA(T_2-T_1)}{l}\\\Rightarrow Q=\frac{0.8\times 2907\times 10^{-6}\times (81-71)\times \frac{5}{9}}{5.6\times 10^{-3}}\\\Rightarrow Q=2.30714\ W

The rate of energy transfer is 2.30714 W

Q=\frac{kA(T_2-T_1)}{l}\\\Rightarrow Q=\frac{0.8\times 2907\times 10^{-6}\times (0-71)\times \frac{5}{9}}{5.6\times 10^{-3}}\\\Rightarrow Q=-16.38071\ W

The rate of energy transfer is -16.38071 W

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<span>The momentum of the second ball will depend on the acceleration of the first moving ball.</span>
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