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3 years ago

Functional groups are a group of molecules attached to a carbon-based core of an organic molecule. Key functional groups are

1 answer:

6 0

Functional groups are most identifiable through rational chemical formulas. In organic chemistry, the most basic functional groups include hydroxyl, carboxyl, carbonyl, ester, ether, and amino functional groups.

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Convert 14.9 inches cubed into ml

ANTONII [103]

244.1673 is your answer

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3 years ago

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What is the reactants start for H2 + O2 --> H2O

zaharov [31]

Answer:

H2 + O2

Explanation:

H2 + O2 --> H2O

The items on the left side is the reactants. The arrow means yields, and the item the arrow is pointing at is the product.

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3 years ago

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In a closed container, the vapor pressure of 10 mL of ethanol at 20 degrees C is 5.85 kPa. What is the vapor pressure of 20 mL o

natulia [17]

Answer:

${P_2}=2.925\ kPa$

Explanation:

At same temperature and same number of moles, Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 10 mL

V₂ = 20 mL

P₁ = 5.85 kPa

P₂ = ?

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${5.85\ kPa}\times {10\ mL}={P_2}\times {20\ mL}$

${P_2}=\frac{{5.85}\times {10}}{20}\ kPa$

${P_2}=2.925\ kPa$

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4 years ago

g A sample of unknown gas has a mass of 1.95 g and occupies 3.00 L at 1.25 atm and 20 C. What is the molar mass of the unknown g

Viktor [21]

Answer:

Molar mass = 12.51 g/mol

Explanation:

V = 3L

P = 1.25 atm

T = 20 C = 20 + 273 = 293 K (Upon conversion to kelvin temperature)

n =?

m = 1.95g

Molar mass = ?

The variables are related by the follwing equation;

pV = nRT

where r = gas constant = 0.0821 L atm K−1

Solving for n, we have;

n = pV / RT

n = (1.25 * 3 ) / (0.0821 * 293)

n = 3.75 / 24.0553 = 0.1559 mol

The relationship between number of moles, n and molar mass is given as;

n = mass / molar mass

Molar mass = Mass / n = 1.95 / 0.1559

Molar mass = 12.51 g/mol

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4 years ago

C4H10+ 02 → _CO2 + __ H20

Svetllana [295]

Answer:a) 2C4H10 + 13O2 —> 8CO2 + 10H2O. Oxidation reaction

b) 8 (4 moles CO2 per mole butane)

Explanation:

could be written C4H10 + 6 1/2 O2 —> 4CO2 + 5H2O

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3 years ago