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3 years ago

15

Which of the following molecules has an angular (bent) geometry that is commonly represented as a resonance hybrid of two or mor

e electron-dot structures?(A) CO2 (B) O3 (C) CH4 (D) BeF2 (E) OF2

1 answer:

hoa [83]3 years ago

4 0

Answer: B

Explanation: The figure below shows the dot and resonance structure of ozone and the structures.

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What is the manipulated variable in maria experiment what is the responding variable

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What are the variables you have? I can't answer if I don't know? Haha. :)

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3 years ago

Convert 500 inches to m. <br> 1000mm =1m<br> 1inch = 2.54 cm <br> 10mm=1cm

stira [4]

Answer:

12.7m

Explanation:

FORMULA

for an approximate result, divide the length value by 39.370078

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3 years ago

The combustion of hydrogen-oxygen mixtures is used to produce very high temperatures (ca. 2500 °C) needed for certain types of w

tangare [24]

Answer:

1360kJ are evolved

Explanation:

When 1mole of H2 reacts with 1/2 moles O2 producing 1 mole of water and 241.8kJ.

To solve this question we need to find the limiting reactant knowing were added 90g of H2 and 90g of O2 as follows:

<em>Moles H2 -Molar mass: 2g/mol-</em>

90g H2 * (1mol / 2g) = 45 moles

<em>Moles O2 -Molar mass: 32g/mol-</em>

90g * (1mol / 32g) = 2.81moles

For a complete reaction of 2.81 moles of O2 are needed:

2.81 moles O2 * (1mol H2 / 1/2 mol O2) = 5.62 moles H2

As there are 45 moles, H2 is the excess reactant and O2 the limiting reactant.

As 1/2 moles O2 produce 241.8kJ, 2.81 moles will produce:

2.81 moles O2 * (241.8kJ / 1/2moles O2) =

<h3>1360kJ are evolved</h3>

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3 years ago

The recommended daily requirement of calcium is1,000 mg. Tap water in a Midwestern city contains approximately 150 mgCa/L. A per

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The answer is D. 30 percent

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4 years ago

Convert the following into balanced equations. ( Use the lowest possible coefficents)?(a) When gallium metal is heated in oxygen

ehidna [41]

Answer:

Explanation:

(a) Balanced reaction of gallium with oxygen is as follows:

$4Ga(s)+3O_2(g) \rightarrow 2Ga_2O_3 (s)$

(b) $C_6H_{14}(l)+O_2(g)\rightarrow CO_2(g)+H_2O(l)$

Multiply the carbon dioxide by 6 to balance carbon as follows:

$C_6H_{14}(l)+O_2(g)\rightarrow 6CO_2(g)+H_2O(l)$

After that multiply H2O by 7 to balance hydrogen as follows:

$C_6H_{14}(l)+O_2(g)\rightarrow CO_2(g)+7H_2O(l)$

Finally balance oxygen by multiplying O2 by 19/2. Therefore, balanced reaction is as follows:

$C_6H_{14}(l)+\frac{19}{2} O_2(g)\rightarrow 6CO_2(g)+7H_2O(l)$

(c) $Na_3PO_4(s)+CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl$

first balance calcium, by multiply $CaCl_2$ by 3 as follows:

$Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl$

After that balance phosphorous by multiplying $Na_3PO_4$ by 2 as follows:

$2Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl$

Finally balance Na by multiplying NaCl by 6. Therefore, balance reaction is as follows:

$2Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+6NaCl$

3 0

3 years ago