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3 years ago

How do you find distance on a velocity time graph?

Physics

1 answer:

vekshin13 years ago

8 0

The region under the speed time chart gives the relocation.

In simple to-recall, straightforward terms, remove levels with the result of speed and time. So when you discover the region under a speed time diagram, you are really increasing speed and time. This gives the separation.

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An electron moving in the direction of the +x-axis enters a magnetic field. If the electron experiences a magnetic deflection in

algol13

Answer:

- z axis

Explanation:

The magnetic force is perpendicular to its speed and the direction of the magnetic field, its equation being

F = q v x B

Where the bold indicates vectors, q is a positive charge,

The way to use this equation is with the rule of the right hand, the thumb points in the direction of the velocity, the other fingers extended in the direction of the magnetic field and the palm is the direction of the force for a positive charge.

Let's apply this to our case the speed is on the x axis and the force in ex. negative Y axis, the other fingers point perpendicular to the sheet, but since the charge is negative the magnetic field enters the sheet, this would be the negative z axis

8 0

3 years ago

Very large accelerations can injure the body, especially if they last for a considerable length of time. The severity index (SI)

Ludmilka [50]

Answer:

a) The severity index (SI) is 3047.749, b) The injured travels 0.345 meters during the collision.

Explanation:

a) The g-multiple of the acceleration, that is, a ratio of the person's acceleration to gravitational acceleration, is:

$a' = \frac{35\,\frac{m}{s^{2}} }{9.807\,\frac{m}{s^{2}} }$

$a' = 3.569$

The time taken for the injured to accelerate to final speed is given by this formula under the assumption of constant acceleration:

$v_{f} = v_{o} + a \cdot t$

Where:

$v_{o}$ - Initial speed, measured in meters per second.

$v_{f}$ - Final speed, measured in meter per second.

$a$ - Acceleration, measured in $\frac{m}{s^{2}}$ .

$t$ - Time, measured in seconds.

$t = \frac{v_{f}-v_{o}}{a}$

$t = \frac{\left(12\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s} \right)}{35\,\frac{m}{s^{2}} }$

$t = 0.095\,s$

Lastly, the severity index is now determined:

$SI = \frac{a'^{5}}{2\cdot t}$

$SI = \frac{3.569^{5}}{2\cdot (0.095\,s)}$

$SI = 3047.749$

b) The initial and final speed of the injured are $1.944\,\frac{m}{s}$ and $5.278\,\frac{m}{s}$ , respectively. The travelled distance can be determined from this equation of motion: