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Mashutka [201]
3 years ago
11

Please help I’ll name you brainliest and give five stars please

Physics
1 answer:
OLga [1]3 years ago
7 0

Answer:

i think its 10 or 11 not sure though if its wrong im sorry im trying to help

Explanation:

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Ex 3) A tennis player lobs the tennis ball up in the air during a serve at a rate 3 m/s.
slega [8]

Explanation:

s=(v^2-u^2)/2g

=(0-3^2)/2*10

= 0.45m

3 0
2 years ago
To determine the pressure in a fluid at a given depth with the air-filled cartesian diver, we can employ Boyle's law, which stat
aniked [119]

Answer:

The pressure at this depth is 1.235\cdot P_{atm}.

Explanation:

According to the statement, the uncompressed fluid stands at atmospheric pressure. By Boyle's Law we have the following expression:

\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}} (1)

Where:

V_{1}, V_{2} - Initial and final volume.

P_{1}, P_{2} - Initial and final pressure.

If we know that V_{2} = 0.81\cdot V_{1}, then the pressure ratio is:

\frac{P_{2}}{P_{1}} = 1.235

If P_{1} = P_{atm}, then the final pressure of the gas is:

P_{2} = 1.235\cdot P_{atm}

The pressure at this depth is 1.235\cdot P_{atm}.

6 0
2 years ago
When energy is transformed, the amount of usable energy?
cricket20 [7]
Cannot be determined, I need more information.
7 0
3 years ago
Q.) Miscellaneous conversations. a) mass=120*10^8 g (Convert this value in mg and kg Write in standard form after converting) b)
aleksley [76]

Answer:

a. Convert  120 × 10⁸ g to i mg = 1.2 × 10¹³ mg ii. to g = 1.2 × 10⁷ kg

b. Convert 200000 × 10³ m to i. micrometers = 0.2 × 10³ μm  ii. to cm = 2 × 10⁶ cm iii. to km = 2 × 10⁵ km

Explanation:

a. i. To convert the mass = 120 × 10⁸ g to mg, We know that 1000 mg = 10³ mg = 1 g, Since we are converting to mg, 120 × 10⁸ g = 120 × 10⁸ × 1g = 120 × 10⁸ × 10³ mg = 120 × 10¹¹ mg = 1.2 × 10² × 10¹¹ mg = 1.2 × 10¹³ mg

ii. To convert the mass = 120 × 10⁸ g to kg, We know that 1000 g = 10³ g = 1 kg, 1 g = 10⁻³ kg. Since we are converting to kg, 120 × 10⁸ g = 120 × 10⁸ × 1g = 120 × 10⁸ × 10⁻³ kg = 120 × 10⁵ kg = 1.2 × 10² × 10⁵ kg = 1.2 × 10⁷ kg

b. i.To convert the length = 200000 × 10³ m to micrometers, We know that 1/1000000 μm = 10⁻⁶ mg = 1 m, Since we are converting to micrometers, μm, 200000 × 10³ m = 200000 × 10³ × 1 m = 200000 × 10³ ×  1/1000000 μm = 200000/1000000 × 10³ μm = 0.2 × 10³ μm

ii. To convert the length = 200000 × 10³ m to cm, We know that 100 cm = 10² cm = 1 m, 1 m = 10⁻² cm = 1/100 cm. Since we are converting to cm, 200000 × 10³ m = 200000 × 10³ × 1 m = 200000 × 10³ × 1/100 cm = 200000/100 × 10³ cm = 2000 × 10³ cm  = 2 × 10³ × 10³ cm = 2 × 10⁶ cm

iii. To convert the length = 200000 × 10³ m to km, We know that 1000 m = 10³ m = 1 km, 1 m = 10⁻³ km = 1/1000 km Since we are converting to km, 200000 × 10³ m = 200000 × 10³ × 1 m = 200000 × 10³ ×  1/1000 km = 200000/1000 × 10³ km = 200 × 10³ km = 2 × 10² × 10³ km = 2 × 10⁵ km

8 0
3 years ago
Assume that the cart is free to roll without friction and that the coefficient of static friction between the block and the cart
Dahasolnce [82]

Answer:F=\frac{(M+m)g}{\mu _s}

Explanation:

Given

Trolley of mass M is free to roll without friction

coefficient of friction between trolley and mass m is \mu _s

Force F is applied on mass m

Acceleration of the system is

a=\frac{F}{M+m}

friction Force will balance weight of block

friction force=\mu _sN

N=ma

\mu _sN=mg

\mu _sma=mg

\mu _s=\frac{g}{a}

F=\frac{(M+m)g}{\mu _s}

6 0
3 years ago
Read 2 more answers
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