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CaHeK987 [17]
3 years ago
13

The half-life of substance-X is 5 minutes. If you start with 20g of substance-X, how much substance-X is leftover after 5 minute

s? How about 10 minutes?
Chemistry
1 answer:
timurjin [86]3 years ago
4 0
<span>At 20g with half-life of 5 minutes there would be 10g leftover in 5 minutes. In 10 mins, there would be 5g leftover. Half-life is actually what it says, it refers to time it takes for half of the active elements, etc to break down at which time the potency of the "product" is half as strong. This term is used mainly with radioactive items or medicines.</span>
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Gemiola [76]

Answer:

0.480 grams

Explanation:

Li₃N(s) + 3D₂O (L) --------------------------> ND₃(g) + 3LiOD (aq)

1             :  3                                            : 1           :  3

Number of moles (n) = Mass in gram/ Molar Mass

Mass of ND₃ = 160 mg

                     = 0.16 g

Molar mass of ND₃=  [14 + (3 x 2.014 )]

                               =    14 + 6.042

                               =  20.042 g/mol

Number of moles of   ND₃  =  0.16/20.042

                                             =  0.007983 moles

From the reaction equation, the mole ratio between   Heavy water (D₂O ) and  ND₃ is  3: 1.

This implies that the number of moles of   Heavy water (D₂O )  required

= 3  x 0.007983 moles

=  0.023949 moles

Molar mass of  Heavy water (D₂O )=  [(2.014 x 2) + 16]

                                                           =  20.028 g/mol

Mass in grams of Heavy water (D₂O )= Number of moles  x Molar mass

                                                            =   0.023949   x  20.028

                                                            =  0.4797 grams

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