A. Nitrate is the reduced element.
B. Phosphorus is the oxidized element.
C. oxidation half reaction: P4 + 4H2O ⇒ H2PO4- + 6H+ + 5e
D. Reduction half reaction: NO3- +4H+ 3e- ⇒ NO + 2H2O
Explanation:
P4 + NO3–→ H2PO4– + NO(A)
nitrate is the reduced element as it has lower its oxidation state.
phosphorus is the oxidised element as it has increase in oxidation number.
B) OXIDATION REACTION:
Phosphorus has undergone oxidation from P0 to P5
P4 + 4H2O ⇒ H2PO4- + 6H+ + 5e-
C) REDUCTION REACTION:
Nitrate ion had undergone reduction from nitrate anion to nitrous oxide.
N+5 to N+2
NO3- +4H+ 3e- ⇒ NO + 2H2O
REDOX REACTION:
now multiplying oxidation reaction with 3 and the reduction reaction with 5
P4 + 5NO3- +2H+ + 2H2O⇒ 5NO+3H3PO4-
The atom positions in a general molecule of formula (not shape class) AXn that has shape square pyramidal at the corers of square and one at the above center of the square.
<h3>What is square pyramidal?</h3>
The square pyramidal is a shape geometry of the hybridization in which it consists of one lone pair and 5 bond pairs of electrons that repel each other and due to which the geometry changes from octahedral to square pyramidal.
As atoms are located at the four corners of the planer and one atom at the above center of the planner which is repelled by 4 atoms present at the corner of the planer.
Therefore, the atom positions in a general molecule of formula (not shape class) AXn that has a shape square pyramidal at the corners of the square and one at the above center of the square.
Learn more about square pyramidal, here;
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In short, I’d say the answer is C.
In solids, the intermolecular force of attraction is very high. Whereas, in liquids the intermolecular force of attraction is somewhat less than solids. ... so when you heat, less amount of heat can free the molecules in liquids than solids and hence they heat faster.
The answer is C since both charge and mass have to be balanced on both sides of the equation.
Answer:
48 molecules of CO₂
Explanation:
I think you made a mistake in your question. The formula for propane is C₃H₈, not C₃H₃. But, I will give you the answer for both cases.
For C₃H₃:
First you have to balance the equation.
4 C₃H₃ + 15 O₂ ⇒ 12 CO₂ + 6 H₂O
Next, you need to use the mole ratios between C₃H₃ and CO₂ to find the amount of molecules of CO₂ you will produce with the given amount of C₃H₃.
(16 mol's C₃H₃) × (12 mol's CO₂/4 mol's C₃H₃) = 48 mol's CO₂
You will get 48 molecules of CO₂.
For C₃H₈:
Balance the equation.
C₃H₈ + 5 O₂ ⇒ 3 CO₂ + 4 H₂O
Use the mole ratios between C₃H₈ and CO₂.
(16 mol's C₃H₈) × (3 mol's CO₂/1 mol's C₃H₈) = 48 mol's CO₂
You will get 48 molecules of CO₂ for this equation as well.