Answer:
Actualmente estoy trabajando en una pregunta diferente en este momento.
Explanation:
Actualmente estoy trabajando en una pregunta diferente en este momento.
Problem solving is the act of orderly searching for solutions to problem
The correct option that involves approaching a problem in a new way is the option;
Creative thinking
The reasons why creative thinking is the correct option is given as follows;
Finding new ways to approach a problem, involves considering alternatives to already known approaches to the problem
Given that the options to be considered are to be options which have not been applied, then the process does not involve;
Context: Which looks at the variables that relate the problem with setting or circumstance that aid understanding of the problem
Critical thinking; Which is based on the analysis of the known facts, but the new proposals are required
Perseverance; Which involves adherence to a particular option despite delay or difficulty
However;
Creative thinking; Creative thinking involves the consideration of a situation thing or problem in a new way or by approaching a task differently than what was considered a regular approach, which involves finding an unused or imaginative approach to a problem
Therefore;
The option that involves finding new ways to approach a problem is <u>creative thinking</u>
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Learn lore about problem solving here:
brainly.com/question/24528689
Answer:
The question has some details missing : The 35-kg block A is released from rest. Determine the velocity of the 13-kgkg block BB in 4 ss . Express your answer to three significant figures and include the appropriate units. Enter positive value if the velocity is upward and negative value if the velocity is downward.
Explanation:
The detailed steps and appropriate calculation is as shown in the attached file.
Answer:
a) v = +/- 0.323 m/s
b) x = -0.080134 m
c) v = +/- 1.004 m/s
Explanation:
Given:
a = - (0.1 + sin(x/b))
b = 0.8
v = 1 m/s @ x = 0
Find:
(a) the velocity of the particle when x = -1 m
(b) the position where the velocity is maximum
(c) the maximum velocity.
Solution:
- We will compute the velocity by integrating a by dt.
a = v*dv / dx = - (0.1 + sin(x/0.8))
- Separate variables:
v*dv = - (0.1 + sin(x/0.8)) . dx
-Integrate from v = 1 m/s @ x = 0:
0.5(v^2) = - (0.1x - 0.8cos(x/0.8)) - 0.8 + 0.5
0.5v^2 = 0.8cos(x/0.8) - 0.1x - 0.3
- Evaluate @ x = -1
0.5v^2 = 0.8 cos(-1/0.8) + 0.1 -0.3
v = sqrt (0.104516)
v = +/- 0.323 m/s
- v = v_max when a = 0:
-0.1 = sin(x/0.8)
x = -0.8*0.1002
x = -0.080134 m
- Hence,
v^2 = 1.6 cos(-0.080134/0.8) -0.6 -0.2*-0.080134
v = sqrt (0.504)
v = +/- 1.004 m/s
