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lubasha [3.4K]
4 years ago
9

A certain process requires 3.0 cfs of water to be delivered at a pressure of 30 psi. This water comes from a large-diameter supp

ly main in which the pressure remains at 60 psi. If the galvanized iron pipe connecting the two locations is 200 ft long and contains six threaded 90o elbows, determine the pipe diameter. Elevation differences are negligible.

Engineering
1 answer:
noname [10]4 years ago
3 0

Answer:

diameter of the pipe = 0.4932ft.

Explanation:

assuming d = 0.4932

Re = 3.16 x 10∧5/0.4932

= 6.4 x 10 ∧5

E/d = 0.0005/0.4932

= 0.0010 from moody chat t = 0.02

if 0.02 is beign substituted in equation 2 we will get the same required diameter of the pipe which is 0.4932ft.

check the attachment  for better explanation.thanks

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A solid shaft and a hollow shaft of the same material have same length and outer radius R. The inner radius of the hollow shaft
alexandr402 [8]

Answer with Explanation:

By the equation or Torque we have

\frac{T}{I_{p}}=\frac{\tau }{r}=\frac{G\theta }{L}

where

T is the torque applied on the shaft

I_{p} is the polar moment of inertia of the shaft

\tau is the shear stress developed at a distance 'r' from the center of the shaft

\theta is the angle of twist of the shaft

'G' is the modulus of rigidity of the shaft

We know that for solid shaft I_{p}=\frac{\pi R^4}{2}

For a hollow shaft I_{p}=\frac{\pi (R_o^4-R_i^4)}{2}

Since the two shafts are subjected to same torque from the relation of Torque we have

1) For solid shaft

\frac{2T}{\pi R^4}\times r=\tau _{solid}

2) For hollow shaft we have

\tau _{hollow}=\frac{2T}{\pi (R^4-0.7R^4)}\times r=\frac{2T}{\pi 0.76R^4}

Comparing the above 2 relations we see

\frac{\tau _{solid}}{\tau _{hollow}}=0.76

Similarly for angle of twist we can see

\frac{\theta _{solid}}{\theta _{hollow}}=\frac{\frac{LT}{I_{solid}}}{\frac{LT}{I_{hollow}}}=\frac{I_{hollow}}{I_{solid}}=1.316

Part b)

Strength of solid shaft = \tau _{max}=\frac{T\times R}{I_{solid}}

Weight of solid shaft =\rho \times \pi R^2\times L

Strength per unit weight of solid shaft = \frac{\tau _{max}}{W}=\frac{T\times R}{I_{solid}}\times \frac{1}{\rho \times \pi R^2\times L}=\frac{2T}{\rho \pi ^2R^5L}

Strength of hollow shaft = \tau '_{max}=\frac{T\times R}{I_{hollow}}

Weight of hollow shaft =\rho \times \pi (R^2-0.7R^2)\times L

Strength per unit weight of hollow shaft = \frac{\tau _{max}}{W}=\frac{T\times R}{I_{hollow}}\times \frac{1}{\rho \times \pi (R^2-0.7^2)\times L}=\frac{5.16T}{\rho \pi ^2R^5L}

Thus \frac{Strength/Weight _{hollow}}{Strength/Weight _{Solid}}=5.16

3 0
4 years ago
An airplane travels 1000 miles at velocity of 500 miles in every hour. solve for the time it took the plane to arrive.
alukav5142 [94]

Answer:

Time taken by airplane to cover given distance = 2 hour

Explanation:

Given:

Distance cover by airplane = 1,000 miles

Velocity of airplane = 500 miles per hour

Find:

Time taken by airplane to cover given distance

Computation:

Time taken = Distance / Velocity(Speed)

Time taken by airplane to cover given distance = Distance cover by airplane / Velocity of airplane

Time taken by airplane to cover given distance = 1,000 / 500

Time taken by airplane to cover given distance = 2 hour

7 0
3 years ago
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Flauer [41]

Answer:

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Explanation:

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3 years ago
Would you rather be fishing or hunting?
katen-ka-za [31]

Answer:

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Explanation:

7 0
3 years ago
Read 2 more answers
Guys I really need a lot of help on some engineering questions due tommorrow. If theres anyway your good at this topic pls comen
Olegator [25]

Answer:

I might be able to help

i took engineering for a year so i might be of help! ill try my best but if not i do apologize

7 0
3 years ago
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