<h2>
She will find the ball at a horizontal distance of 86.4 m from landed location</h2>
Explanation:
Consider the vertical motion of ball
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 2 m/s
Acceleration, a = 9.81 m/s²
Displacement, s = 100 m
Substituting
s = ut + 0.5 at²
100 = 2 x t + 0.5 x 9.81 xt²
4.905t² + 2t - 100 = 0
t = 4.32 s or t = -4.72 s
After 4.32 seconds the ball reaches ground.
Now we need to find horizontal distance traveled by ball in 4.32 seconds.
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 20 m/s
Acceleration, a = 0 m/s²
Time, t = 4.32 s
Substituting
s = ut + 0.5 at²
s = 20 x 4.32 + 0.5 x 0 x 4.32²
s = 86.4 m
She will find the ball at a horizontal distance of 86.4 m from landed location
Hey there,
Your correct answer would be proximity. Proximity is <span>principle illustrates our tendency to group items together based on how close they are to each other.
~Jurgen</span>
F = M (V^2/r) = 20 x 100 /.15 =13333.33 N<span>convert units as needed to wind up with Newtons Kg-m/s^2 hope it helps :)</span>
