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Pavlova-9 [17]
3 years ago
11

An object is moving at 2.50 m/s [E]. At a time 3.00 seconds later the object is traveling at 1.50 m/s

Physics
1 answer:
babunello [35]3 years ago
7 0

Given parameters:

First velocity  = 2.50m/s

Time of travel = 3s

Second velocity  = 1.50m/s

Unknown:

The displacement during the first interval = ?

Velocity is the displacement of a body with time. Displacement is a distance move in a specific direction by a body.

    Velocity  = \frac{Displacement}{Time taken}

So;

      Displacement  = Velocity x Time taken

Now input the parameter for the first velocity and time of travel;

      Displacement  = 2.5 x 3  = 7.5m

The displacement id 7.5m

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Answer:

The time where the avergae speed equals the instaneous speed is T/2

Explanation:

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v_{ave} = \frac{1}{T}\int\limits^T_0 {v(t)} \, dt

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We can esaily note that when <u><em>t=T/2</em></u><u><em> </em></u>

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Now we want to know where the car should be, the osition of the car is:

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A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle
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Answer:

a) t = 4.16 s

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Explanation:

Given

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<em />

then we can apply <em>I = II</em>

21.5t + 3t² = 52 + 21.5t

⇒ 3t² = 52

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b) We can use <em>I</em> or <em>II</em>, then

x = 52 + 21.5*(4.16)

⇒ x = 141.51 m

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