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Taya2010 [7]
3 years ago
5

A 20 ml sample of .875 m hcl solution was diluted t o150 ml. calculate the molarity of the resulting solution

Chemistry
1 answer:
Veronika [31]3 years ago
4 0
0.11666667 because M1V1=M2V2
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Just study the thing don't expect others to just answer the homework for you

Explanation:

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What mass of hydrochloric acid (in grams) can 2.7 g of sodium bicarbonate neutralize? (Hint: Begin by writing a balanced equatio
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Answer:

1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate

Explanation:

Step 1: Data given

Mass of sodium bicarbonate = 2.7 grams

Step 2: The balanced equation

HCl + NaHCO3 ⇔  NaCl + H2O + CO2

Step 3: Calculate moles NaHCO3

moles NaHCO3 =2.7 g / 84 g/mol= 0.032 moles

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Step 5: Calculate mass HCl

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mass HCl = 0.032 * 36.46 g/mol= 1.17 grams

1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate

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Explanation:

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