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alexdok [17]
2 years ago
15

Sample Response: Forces are either positive or negative vectors, depending on the direction in which the force is acting. The ne

t force is the sum of all of the forces acting on an object. If the children pull on the toy with the same force in opposite directions, the forces will be perfectly balanced and cancel out, leaving a net force of zero.
What did you include in your response? Check all that apply.

Forces are vectors.
Forces can be positive or negative.
The forces exerted by the children are in balance.
The net force is the sum of all of the forces that canceled out to zero.
Chemistry
2 answers:
lianna [129]2 years ago
8 0

The net force is the sum of all of the forces that cancelled out to zero. Hence, option D is correct.

<h3>What is force?</h3>

The pushes or pulls on an object with mass causes it to change its velocity.

The net force is the vector sum of all forces acting on an object. Force is a vector quantity.

Two forces of equal magnitude when acting on an object in opposite directions will cancel out each other.

As a result net force is equal to 0. The word net here shows the total force acting on the object.

Hence, option D is correct.

Learn more about the force here:

brainly.com/question/14902131

#SPJ1

Varvara68 [4.7K]2 years ago
7 0

  • The net force is the sum of all of the forces that cancelled out to zero. Hence, option D is correct.

What is force?

  • The pushes or pulls on an object with mass causes it to change its velocity.

  • The net force is the vector sum of all forces acting on an object. Force is a vector quantity.

  • Two forces of equal magnitude when acting on an object in opposite directions will cancel out each other.

  • As a result net force is equal to 0. The word net here shows the total force acting on the object.

<u>Hence, option D is correct.</u>

<em><u>▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬</u></em>

<em><u /></em>

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Explanation:

The given data is as follows.

Volume of water = 0.25 m^{3}

Density of water = 1000 kg/m^{3}

Therefore,  mass of water = Density × Volume

                       = 1000 kg/m^{3} \times 0.25 m^{3}

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Initial Temperature of water (T_{1}) = 20^{o}C

Final temperature of water = 140^{o}C

Heat of vaporization of water (dH_{v}) at 140^{o}C  is 2133 kJ/kg

Specific heat capacity of water = 4.184 kJ/kg/K

As 25% of water got evaporated at its boiling point (140^{o}C) in 60 min.

Therefore, amount of water evaporated = 0.25 × 250 (kg) = 62.5 kg

Heat required to evaporate = Amount of water evapotaed × Heat of vaporization

                           = 62.5 (kg) × 2133 (kJ/kg)

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The power rating of electric heating element is 37 kW.

Hence, heat required to raise the temperature from 20^{o}C to 140^{o}C of 250 kg of water = Mass of water × specific heat capacity × (140 - 20)

                      = 250 (kg) × 40184 (kJ/kg/K) × (140 - 20) (K)

                     = 125520 kJ  

Time required = Heat required / Power rating

                       = \frac{125520}{37}

                       = 3392 sec

Time required to raise the temperature from 20^{o}C to 140^{o}C of 0.25 m^{3} water is calculated as follows.

                    \frac{3392 sec}{60 sec/min}

                     = 56 min

Thus, we can conclude that the time required to raise the temperature is 56 min.

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