Question

The following chemical reaction takes place in aqueous solution: AgNO3 (aq) + NaBr (aq) → AgBr (s) + NaNO3 (aq) Write the net ionic equation for this reaction.

Answer 1

Answer: The net ionic equation is written below.

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of silver nitrate and sodium bromide is given as:

$AgNO_3(aq.)+NaBr(aq.)\rightarrow AgBr(s)+NaNO_3(aq.)$

Ionic form of the above equation follows:

$Ag^+(aq.)+NO_3^-(aq.)+Na^+(aq.)+Br^-(aq.)\rightarrow AgBr(s)+Na^+(aq.)+NO_3^-(aq.)$

As, sodium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$Ag^+(aq.)+Br^-(aq.)\rightarrow AgBr(s)$

Hence, the net ionic equation is written above.

Answer 2

AgNO3(ag)  +  NaBr(aq)  ---->  AgBr(s)  +  NaNO3(aq)


the  ionic  equation

 Ag+(aq)   +  NO3-(aq)  +  Na +(aq)  +Br-(aq)    ----->  AgBr(s)  +  Na+(aq)    +    NO3-(aq)

cancel  the  spectator  ions  in  this  case  Na+   and  No3-

the net  ionic  equation  is therefore =

Ag+(aq)  +   Br-(aq)  ---->  AgBr  (s)