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Flauer [41]
3 years ago
11

If a catalyst is used in a reaction,

Chemistry
1 answer:
Ann [662]3 years ago
4 0
If a catalyst is used in a reaction, C. The reaction rate increases.
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What pressure is exerted by 0.750 mol of a gas at 0 °C and a volume of 5
kow [346]

Answer: 3.4 atm

Explanation:

Given that:

Volume of gas V = 5L

(since 1 liter = 1dm3

5L = 5dm3)

Temperature T = 0°C

Convert Celsius to Kelvin

(0°C + 273 = 273K)

Pressure P = ?

Number of moles of gas n = 0.75 moles

Note that Molar gas constant R is a constant with a value of 0.0821 atm dm3 K-1 mol-1

Then, apply ideal gas equation

pV = nRT

p x 5dm3 = 0.75 moles x (0.0821 atm dm3 K-1 mol-1 x 273K)

p x 5dm3 = 16.8 atm dm3

p = (16.8 atm dm3 / 5dm3)

p = 3.4 atm

Thus, a pressure of 3.4 atm is exerted by the gas.

7 0
4 years ago
Word Bank
kiruha [24]
Kingdom, phylum or division, class, order, family, genus, species 
7 0
4 years ago
2 H2(g) + O2(g) → 2 H2O(g)
alexgriva [62]

Answer:

77 L of water can be made.

Explanation:

Molar mass of O_{2} = 32 g/mol

So, 55 g of O_{2} = \frac{55}{32} mol of  O_{2} = 1.72 mol of  O_{2}

As hydrogen is present in excess amount therefore  O_{2} is the limiting reagent.

According to balanced equation, 1 mol of  O_{2} produces 2 mol of H_{2}O.

So, 1.72 mol of O_{2} produce (2\times 1.72) mol of H_{2}O or 3.44 mol of H_{2}O.

Let's assume H_{2}O gas behaves ideally at STP.

Then, P_{H_{2}O}.V_{H_{2}O}=n_{H_{2}O}.R.T   , where P, V, n, R and T represents pressure, volume, no. of moles, gas constant and temperature in kelvin scale respectively.

At STP, pressure is 1 atm and T is 273 K.

Here, n_{H_{2}O} = 3.44 mol and R = 0.0821 L.atm/(mol.K)

So, (1atm)\times V_{H_{2}O}=(3.44mol)\times (0.0821L.atm.mol^{-1}.K^{-1})\times (273K)

  \Rightarrow  V_{H_{2}O}=77L

Option (b) is correct.

5 0
3 years ago
Define the term ionization energy. Choose one:
olga nikolaevna [1]

Answer:

A. The amount of energy needed to remove 1 mole of electrons from 1 mole of ground-state atoms or ions in the gas phase.

Explanation:

Ionization energy is the quantity of energy required to remove an electron in ground electronic state from an isolated gaseous atom or ion, resulting in a cation.  kJ/mol is the expresion we use for this energy, it refers to the amount of energy it takes for all the atoms in a mole to lose one electron each.

 Ionization energy can be used as an indicator of reactivity and can be used to help predict the strength of chemical bonds because the more electrons are lost, the more positive the ion will be and the harder it will be to separate the electrons from the atom.

I hope you find this information useful and interesting! Good luck!    

8 0
3 years ago
2 points
prohojiy [21]

Answer: An imbalance of electric charge I the surface of an object

-electric charges that are stationary or at rest

-charges that build up on an object

7 0
3 years ago
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