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Zolol [24]
3 years ago
9

The Bessemer process created strong, lightweight (1 point) steel. oil. iron. coal.

Chemistry
2 answers:
joja [24]3 years ago
8 0

United States History A Unit 2: Industrialization of the United States.

1.A Steel

2.A Laissez-faire

3.B Asia

4.C Dramatically Expanded

5.D Were a variety of musical drama, songs, and comedy.

6.B Farmed in many different ways.

7.B Was the last conflict between Native Americans and the government.

8.B African Americans who fled the South after Reconstruction.

9.B The invention of barbed wire.

10.A Jim Crow Laws.

11.D The National Grange.

12.C The Style of Politics in the United States.

13.C Populist Leader.

14.D  All of the above.

15.B Was arrested for voting in an election in New York.

16.D filling important Government positions with party supporters.

17.C Be Trained In Specific Trade.


All of the answers are correct guaranteed.

Good Luck! Hope I helped:)

Mkey [24]3 years ago
5 0
The correct answer for this question is a steel
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Can someone please answer this science question it’s due tonight!
love history [14]

Answer:

Hope this helps you!

Explanation:

Include big outside heaters and inside heaters to maintain warm

Also wear special clothes to keep body warmth

7 0
3 years ago
People often think bonds store or hold energy. If that is true, should the energy be high or low when a bond forms?
marta [7]

Answer:

The energy should be high.

Explanation:

Bonds do store energy and release it depending if it's endothermic or exothermic. The energy should be low because when a bond forms (endothermic) it releases heat, which helps form bonds. Having a high energy means the bond is absorbing energy, which helps break bonds (endothermic). How this helps!

4 0
3 years ago
TIME REMAINING
jek_recluse [69]

Answer:

Liquid

Explanation:

had this ln a test and got it right

6 0
3 years ago
1. The elements in the modern Periodic Table are arranged according to their
Usimov [2.4K]

Answer:

A). Atomic number

Explanation:

THIS IS EASY

4 0
3 years ago
Apply the given electronegativities to each bond in the examples below to see which are polar and which are nonpolar. Multiple b
Nesterboy [21]

Answer:

H-O-H  polar

O-C-O nonpolar

H-C-N   polar

Explanation:

Looking up the electronegativities of the atoms involved in this question, we have:

Atom   Electronegativity

H               2.2

C               2.55

N               3.04

O               3.44

All of the atoms differ in electronegativity resulting in individual dipole moments in H-O, O-C, H-C and C-N bonds. To find if the molecules will be polar we need to consider the structure of the compound to see if there is a resultant dipole moment.

In H-O-H, we have 2 lone pairs of electrons around the central oxygen atom which push the angle H-O-H  of the ideal tetrahedral structure to be smaller than 109.5 º  resulting in an overall dipole moment making it polar.

In O-C-O, we have two dipole moments that exactly cancel each other in the linear molecule  since the central carbon atom does not have lone pairs of electrons since it  has 2 double bonds. Therefore the molecule is nonpolar.

In H-C-N, again we have have a central carbon atom without lone pairs of electrons and the shape of the molecule is linear. But, now we have that the dipole moment in C-N is stronger than the H-C dipole because of the difference in electronegativity of nitrogen compared to hydrogen. The molecule has an overall dipole moment and it is polar.

8 0
3 years ago
Read 2 more answers
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